代码搜索:minimum

找到约 5,594 项符合「minimum」的源代码

代码结果 5,594
www.eeworm.com/read/111695/6153478

java datasetutilities.java

/* ====================================== * JFreeChart : a free Java chart library * ====================================== * * Project Info: http://www.jfree.org/jfreechart/index.html * Pr
www.eeworm.com/read/106597/6191817

c tbdm.c

/* $Log: tbdm.c,v $ Revision 1.1.1.1 2002/07/28 05:23:47 freeman_yong lpc10 codec * Revision 1.1 1996/08/19 22:30:26 jaf * Initial revision * */ #ifdef P_R_O_T_O_T_Y_P_E_S ext
www.eeworm.com/read/105889/6197336

java gridrange.java

/*$************************************************************************************************ ** ** $Id: GridRange.java,v 1.3 2004/04/28 19:40:26 desruisseaux Exp $ ** ** $Source: /cvsroot/g
www.eeworm.com/read/101082/6245122

1 mmapalignment.1

.TH mmapalignment 1 .SH Name mmapalignment \- returns minimum address alignment .SH Syntax \fBmmapalignment\fP .SH Description .NXR "address alignment" .NXR "memory mapping" "address alignment" The .P
www.eeworm.com/read/101082/6247015

1 mmapalignment.1

.TH mmapalignment 1 .SH Name mmapalignment \- returns minimum address alignment .SH Syntax \fBmmapalignment\fP .SH Description .NXR "address alignment" .NXR "memory mapping" "address alignment" The .P
www.eeworm.com/read/255407/6291104

cpp template.cpp

// Section 10.1 // $ CC template.cpp /* minimum of 10 and 20 is: 10 minimum of 10.3 and 20.6 is: 10.3 */ #include using std::cout; using std::endl; template
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m hpso.m

function [x,fval,gfx,output]=hPSO(fitnessfun,nvars,options,varargin) %Syntax: [x,fval,gfx,output]=hPSO(fitnessfun,nvars,options,varargin) %___________________________________________________________
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cpp c9-14.cpp

#include using namespace std; template class Compare {public: Compare(numtype a,numtype b) {x=a;y=b;} numtype max() {return (x>y)?x:y;} numtype min
www.eeworm.com/read/492901/6412600

cpp d11r6.cpp

#include "iostream.h" #include "math.h" double func2(double x[], int n) { return 0.5 - bessj0(pow((x[1] - 1.0) , 2) + pow((x[2] - 2.0), 2) + pow((x[3] - 3.0) , 2)); } double func(d
www.eeworm.com/read/488750/6485101

c selection sort.c

#include #include int minimum(int *a ,int i ,int j) { int k,min = i; for(k=i+1;k a[k]) min = k; return min; } void