代码搜索：minimum
找到约 5,594 项符合「minimum」的源代码
代码结果 5,594
www.eeworm.com/read/142897/12911162
asl p364fdc.asl
Device(FDC0)
{
Name(_HID, EISAID("PNP0700")) // PnP Device ID
Method(_STA,0)
{
Store(Zero,LDN_)
If(ACTR)
{
www.eeworm.com/read/142897/12911311
asl p364midi.asl
Device(MIDI)
{
Name(_HID, EISAID("PNPB006")) // PnP Device ID Midi Type
Method(_STA,0)
{
Store(0x0C,LDN_)
If(ACTR)
www.eeworm.com/read/142897/12911795
asl p364uar2.asl
Device(COMB)
{
Name(_HID,EISAID("PNP0501"))
Name(_UID,0x02)
Method(_STA,0)
{
Store(0x02,LDN_) // set logical device number for Serial Port 2
www.eeworm.com/read/243661/12928762
c tbdm.c
/***********************************************************************
*
* TBDM Version 49
*
**********************************************************************
*
* TURBO DIFMAG: Compute H
www.eeworm.com/read/329331/12960109
m min.m
%列状数据最小值
%例如
% A=[11 4 0.2;22 3 0.5;0 3 0.4];
% min(A)
%
%MIN Smallest component.
% For vectors, MIN(X) is the smallest element in X. For matrices,
% MIN(X) is a row vector contain
www.eeworm.com/read/141545/13001922
c min_max.c
#include
#include
void main(void)
{
printf("Maximum of %f and %f is %f\n",
10.0, 25.0, max(10.0, 25.0));
printf("Minimum of %f and %f is %f\n",
10.0, 2
www.eeworm.com/read/327870/13058799
cpp random.cpp
/***************************************************************
/* Single & Multi-Objective Real-Coded Genetic Algorithms Code */
/* Author: Kumara Sastry */
/*
www.eeworm.com/read/140851/13059308
m minbrack.m
function [br_min, br_mid, br_max, num_evals] = minbrack(f, a, b, fa, ...
varargin)
%MINBRACK Bracket a minimum of a function of one variable.
%
% Description
% BRMIN, BRMID, BRMAX, NUMEVALS
www.eeworm.com/read/326893/13111078
c minmax.c
#include
#define MIN(x, y) (((x) < (y)) ? (x): (y))
#define MAX(x, y) (((x) > (y)) ? (x): (y))
void main(void)
{
printf("Minimum of 3 and 5 is %d\n", MIN(3, 5));
printf("Max
www.eeworm.com/read/326893/13111151
c min_max.c
#include
#include
void main (void)
{
printf("Maximum of %f and %f is %f\n",
10.0, 25.0, max(10.0, 25.0));
printf("Minimum of %f and %f is %f\n",
10.0,