代码搜索:minimum

找到约 5,594 项符合「minimum」的源代码

代码结果 5,594
www.eeworm.com/read/450470/7483610

c min_max.c

#include #include void main (void) { printf("Maximum of %f and %f is %f\n", 10.0, 25.0, max(10.0, 25.0)); printf("Minimum of %f and %f is %f\n", 10.0,
www.eeworm.com/read/448329/7534881

c hiduse.c

char code HidUseReportDescriptor[47] = { 0x06, 0xA0, 0xFF, // Usage page (vendor defined) 0x09, 0x01, // Usage ID (vendor defined) 0xA1, 0x01, // Collection (application) // The Inp
www.eeworm.com/read/446971/7562169

c ch05.02.c

// #include #include #include /** ** Minimum value: 1 occurs: 5 times. **/ int min( const vector< int > &ivec, int &occurs ) { int minVal = ivec[
www.eeworm.com/read/445950/7587815

c minmax.c

#include #define MIN(x, y) (((x) < (y)) ? (x): (y)) #define MAX(x, y) (((x) > (y)) ? (x): (y)) void main(void) { printf("Minimum of 3 and 5 is %d\n", MIN(3, 5)); printf("Max
www.eeworm.com/read/445950/7587846

c min_max.c

#include #include void main (void) { printf("Maximum of %f and %f is %f\n", 10.0, 25.0, max(10.0, 25.0)); printf("Minimum of %f and %f is %f\n", 10.0,
www.eeworm.com/read/445230/7597824

c minmax.c

#include #define MIN(x, y) (((x) < (y)) ? (x): (y)) #define MAX(x, y) (((x) > (y)) ? (x): (y)) void main(void) { printf("Minimum of 3 and 5 is %d\n", MIN(3, 5)); printf("Max
www.eeworm.com/read/445230/7597855

c min_max.c

#include #include void main (void) { printf("Maximum of %f and %f is %f\n", 10.0, 25.0, max(10.0, 25.0)); printf("Minimum of %f and %f is %f\n", 10.0,
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c minmax.c

#include #define MIN(x, y) (((x) < (y)) ? (x): (y)) #define MAX(x, y) (((x) > (y)) ? (x): (y)) void main(void) { printf("Minimum of 3 and 5 is %d\n", MIN(3, 5)); printf("Max
www.eeworm.com/read/444375/7613380

c min_max.c

#include #include void main (void) { printf("Maximum of %f and %f is %f\n", 10.0, 25.0, max(10.0, 25.0)); printf("Minimum of %f and %f is %f\n", 10.0,
www.eeworm.com/read/441245/7672732

m nfminbnd.m

function nmin = nfminbnd(fun,n1,n2,itermax,varargin) %NFMINBND Private routine for optimizing integer complexity / %regularisation parameters fmin = inf; if n2 - n1 < itermax % smal