代码搜索：minimum
找到约 5,594 项符合「minimum」的源代码
代码结果 5,594
www.eeworm.com/read/452375/7441360
m kruskal.m
%
%---------------------kruskal.m---------------------
%
% Kruskal algorithm for finding minimum spanning tree
%
% Input: PV = nx3 martix. 1st and 2nd row's define the edge (2 vertices) and
www.eeworm.com/read/452050/7449757
cpp 3998700_wa.cpp
/* TU Darmstadt Programming Contest 2001
* Problem: Ship Journey
* Author : Felix Gaertner
* Comment: converted Java solution
*/
#include
#include
#include
www.eeworm.com/read/425813/7454158
cpp ucolor.cpp
/*********************************************/
/* TeeChart Delphi Component Library 4.0 */
/* Demo */
/* Copyright (c) 1995-1998 by David Berneda */
/* A
www.eeworm.com/read/425813/7454183
cpp uscroll.cpp
/*********************************************/
/* TeeChart Delphi Component Library 4.0 */
/* Demo */
/* Copyright (c) 1995-1998 by David Berneda */
/* A
www.eeworm.com/read/451644/7459772
pas unit1.pas
unit Unit1;
interface
uses
Windows, Messages, SysUtils, Classes, Graphics, Controls, Forms, Dialogs,
StdCtrls;
Function FUNC(X:real):real;
Function FUNC2(X:array of real;N:integer):real;
www.eeworm.com/read/451329/7467363
c minmax.c
#include
#define MIN(x, y) (((x) < (y)) ? (x): (y))
#define MAX(x, y) (((x) > (y)) ? (x): (y))
void main(void)
{
printf("Minimum of 3 and 5 is %d\n", MIN(3, 5));
printf("Max
www.eeworm.com/read/451329/7467394
c min_max.c
#include
#include
void main (void)
{
printf("Maximum of %f and %f is %f\n",
10.0, 25.0, max(10.0, 25.0));
printf("Minimum of %f and %f is %f\n",
10.0,
www.eeworm.com/read/450650/7479196
m bungeescript.m
for k=1:50;
[t,x,y]=sim('bungee_cmd');
if min(y)>0
break
end
end
disp(['The minimum safe k is: ',num2str(k)])
www.eeworm.com/read/450639/7479612
c tbdm.c
/***********************************************************************
*
* TBDM Version 49
*
**********************************************************************
*
* TURBO DIFMAG: Compute H
www.eeworm.com/read/450470/7483575
c minmax.c
#include
#define MIN(x, y) (((x) < (y)) ? (x): (y))
#define MAX(x, y) (((x) > (y)) ? (x): (y))
void main(void)
{
printf("Minimum of 3 and 5 is %d\n", MIN(3, 5));
printf("Max