代码搜索：minimum
找到约 5,594 项符合「minimum」的源代码
代码结果 5,594
www.eeworm.com/read/163880/10141278
asl 8661uar1.asl
Device(UAR1) { //Communication Device (Modem Port)
Name (_HID, EISAID("PNP0501")) // PnP ID for ITE8680 UART1 Port
Name(_UID,0x01)
Method (_STA, 0){ // UART1 Device
www.eeworm.com/read/163880/10141365
asl 8661uar2.asl
Device(UAR2) { //Control Methods for RS232 operation
Name(_HID,EISAID("PNP0501")) // PnP ID for ITE8661 UART2 Port
Name(_UID,0x02)
Method (_STA, 0){ // UART2 Device St
www.eeworm.com/read/358694/10181529
m min.m
%列状数据最小值
%例如
% A=[11 4 0.2;22 3 0.5;0 3 0.4];
% min(A)
%
%MIN Smallest component.
% For vectors, MIN(X) is the smallest element in X. For matrices,
% MIN(X) is a row vector contain
www.eeworm.com/read/358270/10193276
m llimit.m
% LLIMIT Limit a vector to a given minimum value
%
% [y] = LLIMIT (x,m) limits vector x to have minimum value m
%
function [y] = llimit (x, m);
y = x;
for q = 1:length(x)
if (x(q) < m
www.eeworm.com/read/281232/10255173
c s35.c
/***************************************************************************
* copyright : (C) 2002 by Hendrik Sattler *
* mail : post@hendrik-sattle
www.eeworm.com/read/281000/10273928
cpp fig06_30.cpp
/**
* Remove the minimum item.
* Throws UnderflowException if empty.
*/
void deleteMin( )
{
if( isEmpty( ) )
throw UnderflowException( );
www.eeworm.com/read/162609/10291396
h melp.h
/*
2.4 kbps MELP Proposed Federal Standard speech coder
Fixed-point C code, version 1.0
Copyright (c) 1998, Texas Instruments, Inc.
Texas Instruments has intellectual property rights on
www.eeworm.com/read/355007/10306341
c minmax.c
#include
#define MIN(x, y) (((x) < (y)) ? (x): (y))
#define MAX(x, y) (((x) > (y)) ? (x): (y))
void main(void)
{
printf("Minimum of 3 and 5 is %d\n", MIN(3, 5));
printf("Max
www.eeworm.com/read/355007/10306460
c min_max.c
#include
#include
void main (void)
{
printf("Maximum of %f and %f is %f\n",
10.0, 25.0, max(10.0, 25.0));
printf("Minimum of %f and %f is %f\n",
10.0,
www.eeworm.com/read/162128/10334100
c minmax.c
#include
#define MIN(x, y) (((x) < (y)) ? (x): (y))
#define MAX(x, y) (((x) > (y)) ? (x): (y))
void main(void)
{
printf("Minimum of 3 and 5 is %d\n", MIN(3, 5));
printf("Max