代码搜索：minimum
找到约 5,594 项符合「minimum」的源代码
代码结果 5,594
www.eeworm.com/read/376040/9334982
txt spss教程.txt
四分位数(Quartiles)、均数(Mean)、中位数(Median)、众数(Mode)、总和(Sum)、
标准差(Std.deviation)、方差(Variance)、全距 (Range)、最小值(Minimum)、最大值(Maximum)、
标准误(S.E.mean)、偏度系数（Skewness）和峰度系数(Kurtosis)
www.eeworm.com/read/179705/9342071
out const.out
light travel time from Earth to Mars:
minimum = 4.3 minutes
maximum = 21.0 minutes
www.eeworm.com/read/375559/9356635
pas unit1.pas
unit Unit1;
interface
uses
Windows, Messages, SysUtils, Classes, Graphics, Controls, Forms, Dialogs,
StdCtrls;
Function FUNC(X:real):real;
Function FUNC2(X:array of real;N:integer):real;
www.eeworm.com/read/375224/9368024
m bungeescript.m
for k=1:50;
[t,x,y]=sim('bungee_cmd');
if min(y)>0
break
end
end
disp(['The minimum safe k is: ',num2str(k)])
www.eeworm.com/read/374083/9421531
h precisio.h
//$$ precisio.h floating point constants
#ifndef PRECISION_LIB
#define PRECISION_LIB 0
#ifndef SystemV // if there is float.h
#ifdef USING_FLOAT
www.eeworm.com/read/177674/9442639
m minbrack.m
function [br_min, br_mid, br_max, num_evals] = minbrack(f, a, b, fa, ...
varargin)
%MINBRACK Bracket a minimum of a function of one variable.
%
% Description
% BRMIN, BRMID, BRMAX, NUMEVALS] = M
www.eeworm.com/read/176823/9483329
m minbrack.m
function [br_min, br_mid, br_max, num_evals] = minbrack(f, a, b, fa, ...
varargin)
%MINBRACK Bracket a minimum of a function of one variable.
%
% Description
% BRMIN, BRMID, BRMAX, NUMEVALS] = M
www.eeworm.com/read/372592/9500916
txt d11r6.txt
Private Sub Command1_Click()
'PROGRAM D11R6
'Driver for routine POWELL
NP = 3
NDIM = NP
FTOL = 0.000001
Dim P(3), XI(3, 3)
For I = 1 To NP
For J = 1 To NP
www.eeworm.com/read/372465/9509801
c minmax.c
#include
#define MIN(x, y) (((x) < (y)) ? (x): (y))
#define MAX(x, y) (((x) > (y)) ? (x): (y))
void main(void)
{
printf("Minimum of 3 and 5 is %d\n", MIN(3, 5));
printf("Max
www.eeworm.com/read/372465/9509846
c min_max.c
#include
#include
void main (void)
{
printf("Maximum of %f and %f is %f\n",
10.0, 25.0, max(10.0, 25.0));
printf("Minimum of %f and %f is %f\n",
10.0,