代码搜索：minimum
找到约 5,594 项符合「minimum」的源代码
代码结果 5,594
www.eeworm.com/read/377279/9284163
asl p364midi.asl
Device(MIDI)
{
Name(_HID, EISAID("PNPB006")) // PnP Device ID Midi Type
Method(_STA,0)
{
Store(0x0C,LDN_)
If(ACTR)
www.eeworm.com/read/377279/9284651
asl p364uar2.asl
Device(COMB)
{
Name(_HID,EISAID("PNP0501"))
Name(_UID,0x02)
Method(_STA,0)
{
Store(0x02,LDN_) // set logical device number for Serial Port 2
www.eeworm.com/read/180601/9301561
c minmax.c
#include
#define MIN(x, y) (((x) < (y)) ? (x): (y))
#define MAX(x, y) (((x) > (y)) ? (x): (y))
void main(void)
{
printf("Minimum of 3 and 5 is %d\n", MIN(3, 5));
printf("Max
www.eeworm.com/read/180601/9301619
c min_max.c
#include
#include
void main (void)
{
printf("Maximum of %f and %f is %f\n",
10.0, 25.0, max(10.0, 25.0));
printf("Minimum of %f and %f is %f\n",
10.0,
www.eeworm.com/read/376638/9311242
java apriori.java
/**
* @(#)Apriori.java
*
* This class controls the various aspects of the program such as candidate
* itemset generation and hashtree population.
*
* @author Adrian Bright
*/
import jav
www.eeworm.com/read/180087/9319960
c~ main.c~
#include
#include
#include"pgcdn.h"
usage(char*prg,char*message)
{
fprintf(stderr,"%s: %s\n",prg,message);
fprintf(stderr,"usage: pgcd a1 a2 a3 a4 a5 a6 .... a
www.eeworm.com/read/180087/9319967
c main.c
#include
#include
#include"pgcdn.h"
usage(char*prg,char*message)
{
fprintf(stderr,"%s: %s\n",prg,message);
fprintf(stderr,"usage: pgcd a1 a2 a3 a4 a5 a6 .... a
www.eeworm.com/read/179954/9329238
cpp minmax1.cpp
/* The following code example is taken from the book
* "The C++ Standard Library - A Tutorial and Reference"
* by Nicolai M. Josuttis, Addison-Wesley, 1999
*
* (C) Copyright Nicolai M. Josutti
www.eeworm.com/read/376114/9331157
c minmax.c
#include
#define MIN(x, y) (((x) < (y)) ? (x): (y))
#define MAX(x, y) (((x) > (y)) ? (x): (y))
void main(void)
{
printf("Minimum of 3 and 5 is %d\n", MIN(3, 5));
printf("Max
www.eeworm.com/read/376114/9331225
c min_max.c
#include
#include
void main (void)
{
printf("Maximum of %f and %f is %f\n",
10.0, 25.0, max(10.0, 25.0));
printf("Minimum of %f and %f is %f\n",
10.0,