代码搜索:minimum

找到约 5,594 项符合「minimum」的源代码

代码结果 5,594
www.eeworm.com/read/286953/8736626

c min_max.c

#include #include void main (void) { printf("Maximum of %f and %f is %f\n", 10.0, 25.0, max(10.0, 25.0)); printf("Minimum of %f and %f is %f\n", 10.0,
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m nfminbnd.m

function nmin = nfminbnd(fun,n1,n2,itermax,varargin) %NFMINBND Private routine for optimizing integer complexity / %regularisation parameters fmin = inf; if n2 - n1 < itermax % smal
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c ch05.02.c

// #include #include #include /** ** Minimum value: 1 occurs: 5 times. **/ int min( const vector< int > &ivec, int &occurs ) { int minVal = ivec[
www.eeworm.com/read/187283/8835215

h limits.h

/* Number of bits in a `char'. */ #define CHAR_BIT 8 /* No multibyte characters supported yet. */ #define MB_LEN_MAX 1 /* Minimum and maximum values a `signed char' can hold. */ #define SCHAR_MIN
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java converterrangemodel.java

/* * Works in 1.1+Swing, 1.4, and all releases in between. * Used by the Converter example. */ import javax.swing.*; import javax.swing.event.*; /** * Based on the source code for DefaultBounded
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c minmax.c

#include #define MIN(x, y) (((x) < (y)) ? (x): (y)) #define MAX(x, y) (((x) > (y)) ? (x): (y)) void main(void) { printf("Minimum of 3 and 5 is %d\n", MIN(3, 5)); printf("Max
www.eeworm.com/read/187002/8885742

c min_max.c

#include #include void main (void) { printf("Maximum of %f and %f is %f\n", 10.0, 25.0, max(10.0, 25.0)); printf("Minimum of %f and %f is %f\n", 10.0,
www.eeworm.com/read/382584/9020127

c minmax.c

#include #define MIN(x, y) (((x) < (y)) ? (x): (y)) #define MAX(x, y) (((x) > (y)) ? (x): (y)) void main(void) { printf("Minimum of 3 and 5 is %d\n", MIN(3, 5)); printf("Max
www.eeworm.com/read/382584/9020179

c min_max.c

#include #include void main (void) { printf("Maximum of %f and %f is %f\n", 10.0, 25.0, max(10.0, 25.0)); printf("Minimum of %f and %f is %f\n", 10.0,
www.eeworm.com/read/382395/9032058

c minmax.c

#include #define MIN(x, y) (((x) < (y)) ? (x): (y)) #define MAX(x, y) (((x) > (y)) ? (x): (y)) void main(void) { printf("Minimum of 3 and 5 is %d\n", MIN(3, 5)); printf("Max