代码搜索：matlab、人工免疫
找到约 10,000 项符合「matlab、人工免疫」的源代码
代码结果 10,000
www.eeworm.com/read/339239/12248582
h engine.h
/*
* @(#)engine.h generated by: makeheader 3.10 Sat May 18 22:03:04 2002
*
* built from: ../include/copyright.h
* engapi.c
* engapiv4.c
* engapiv5.c
* fengapi.c
* f
www.eeworm.com/read/339239/12248599
frm exm12052_1.frm
VERSION 5.00
Begin VB.Form Form1
Caption = "exm12052_1.exe调用MATAB作为DDE服务器"
ClientHeight = 4920
ClientLeft = 60
ClientTop = 345
ClientWidth = 6
www.eeworm.com/read/339239/12248611
c exm12032_1.c
#include //
#include //
#include //
#include "engine.h" //
int PASCAL WinMain (HANDLE hInstance, HANDLE hPrevInstance,
LPSTR lpszCmdLine, int
www.eeworm.com/read/339239/12248613
m exm12032_1.m
% exm12032_1.m
% 注意：运行该文件前，要确认exm12032_1.c在D:\mywork目录上
cd D:\mywork
mex -f D:\MATLAB6p5\bin\win32\mexopts\msvc60engmatopts.bat exm12032_1.c
dir exm12032_1.*
disp('按任意键继续')
pause
!e
www.eeworm.com/read/150725/12268811
m dft.m
%MATLAB PROGRAM
function [Xk]=dft(xn,N)
% To calculate coefficients of DFT
n=[0:1:N-1];
k=n;
WN=exp(-j*2*pi/N);
nk=n'*k;
WNnk=WN.^nk;
Xk=xn*WNnk;
www.eeworm.com/read/150725/12268819
m tmp620.m
%MATLAB PROGRAM 6-20
%Applicaton of Cepstrum Analysis
t=0:0.01:1.49;
sig=sin(2*pi*45*t);
echo=0.5*[zeros(1,20) sig(1:length(t)-20)];
sigecho=sig+echo;
c=cceps(sigecho);
plot(t,c);
xlabel('t(s)
www.eeworm.com/read/150725/12268846
m idfs.m
%MATLAB PROGRAM
function [xn]=idfs(Xk,N)
% To calculate IDFS
n=[0:1:N-1];
k=n;
WN=exp(-j*2*pi/N);
nk=n'*k;
WNnk=WN.^(-nk);
xn=Xk*WNnk/N;
www.eeworm.com/read/150725/12268891
m idft.m
%MATLAB PROGRAM
function [xn]=idft(Xk,N)
% To calculate IDFT
n=[0:1:N-1];
k=n;
WN=exp(-j*2*pi/N);
nk=n'*k;
WNnk=WN.^(-nk);
xn=Xk*WNnk/N;
www.eeworm.com/read/150725/12268903
m derive1.m
syms a0 a1 b1 a2 b2 a3 b3 a4 b4 a5 b5 H1 H2 x; %取n=5求解析解用matlab推导A0,Ai,Bi(i=1,...,7)
y=a0+a1*cos(x)+b1*sin(x)+a2*cos(2*x)+b2*sin(2*x)+a3*cos(3*x)...
+b3*sin(3*x)+a4*cos(4*x)+b4*sin(4*x)+a5*cos(5*x)
www.eeworm.com/read/150725/12268908
m dfs.m
%MATLAB PROGRAM
function [Xk]=dfs(xn,N)
% To calculate coefficients of DFS
n=[0:1:N-1];
k=n;
WN=exp(-j*2*pi/N);
nk=n'*k;
WNnk=WN.^nk;
Xk=xn*WNnk;