代码搜索:malloc

找到约 10,000 项符合「malloc」的源代码

代码结果 10,000
www.eeworm.com/read/442831/7644217

c 10mrsn.c

#include "stdlib.h" #include "math.h" void mrsn(t,h,n,y,eps,k,z,f) void (*f)(); int n,k; double t,h,eps,y[],z[]; { int i,j,m,nn; double aa,bb,x,hh,p,dt,t0,qq,*a,*b,*c,*d,*u
www.eeworm.com/read/442831/7644219

c 10gjfq.c

#include "stdlib.h" #include "math.h" void gjfq(t,h,n,y,eps,k,z,f) void (*f)(); int n,k; double t,h,eps,y[],z[]; { void rkt(); int i,j; double a,qq,*d,*p,*u,*v,*w;
www.eeworm.com/read/442831/7644224

c 10hamg.c

#include "stdlib.h" #include "math.h" void hamg(t,h,n,y,eps,k,z,f) void (*f)(); int n,k; double t,h,eps,y[],z[]; { void rkt(); int i,j,m; double a,q,*b,*d,*u,*v,*w,*g;
www.eeworm.com/read/442831/7644227

c 10pbs.c

#include "stdlib.h" #include "math.h" void pbs(t,h,n,y,eps,f) void (*f)(); int n; double t,h,eps,y[]; { void rkt(); int i,j,k,m,nn,it; double x,hh,dd,q,p,g[10],*b,*d,
www.eeworm.com/read/442831/7644234

c 10adms.c

#include "stdlib.h" #include "math.h" void adms(t,h,n,y,eps,k,z,f) void (*f)(); int n,k; double t,h,eps,y[],z[]; { void rkt(); int i,j,m; double a,q,*b,*e,*s,*g,*d;
www.eeworm.com/read/442831/7644235

c 10wity.c

#include "stdlib.h" void wity(t,y,n,h,k,z,f) void (*f)(); int n,k; double t,h,y[],z[]; { int i,j; double x,*a,*d; a=malloc(n*sizeof(double)); d=malloc(n*sizeof(doubl
www.eeworm.com/read/442831/7644237

c 10gil.c

#include "stdlib.h" #include "math.h" void gil(t,h,y,n,eps,q,f) void (*f)(); int n; double t,h,eps,y[],q[]; { int i,j,k,m,ii; double x,p,hh,r,s,t0,dt,qq,*d,*u,*v,*g; s
www.eeworm.com/read/442220/7656902

c algo6-1.c

/* algo6-1.c 求赫夫曼编码。实现算法6.12的程序 */ #include"c1.h" #include"c6-7.h" int min1(HuffmanTree t,int i) { /* 函数void select()调用 */ int j,flag; unsigned int k=UINT_MAX; /* 取k为不小于可能的值 */
www.eeworm.com/read/441732/7666251

cpp inv.cpp

#include #include double *C,a[100]; double *MatrixInver(double A[],int n) //矩阵转置 { int i,j; double *B=NULL; B=(dou
www.eeworm.com/read/441047/7677020

c 4.3.c

#include #include #define NULL 0 struct HTNode {int weight,parent,lchild,rchild; }; struct HTNode* HT; char** HC; int s1,s2; int *w; char *a; void Select(int j) {int i,t