代码搜索:malloc
找到约 10,000 项符合「malloc」的源代码
代码结果 10,000
www.eeworm.com/read/358056/10196819
c 10adms.c
#include "stdlib.h"
#include "math.h"
void adms(t,h,n,y,eps,k,z,f)
void (*f)();
int n,k;
double t,h,eps,y[],z[];
{ void rkt();
int i,j,m;
double a,q,*b,*e,*s,*g,*d;
www.eeworm.com/read/358056/10196820
c 10wity.c
#include "stdlib.h"
void wity(t,y,n,h,k,z,f)
void (*f)();
int n,k;
double t,h,y[],z[];
{ int i,j;
double x,*a,*d;
a=malloc(n*sizeof(double));
d=malloc(n*sizeof(doubl
www.eeworm.com/read/358056/10196822
c 10gil.c
#include "stdlib.h"
#include "math.h"
void gil(t,h,y,n,eps,q,f)
void (*f)();
int n;
double t,h,eps,y[],q[];
{ int i,j,k,m,ii;
double x,p,hh,r,s,t0,dt,qq,*d,*u,*v,*g;
s
www.eeworm.com/read/358056/10196897
c 4ssgj.c
#include "stdlib.h"
#include "math.h"
#include "stdio.h"
int ssgj(a,n)
int n;
double a[];
{ int i,j,k,m;
double w,g,*b;
b=malloc(n*sizeof(double));
for (k=0; k
www.eeworm.com/read/358056/10196904
c 9mtml.c
#include "stdlib.h"
#include "math.h"
#include "3rnd1.c"
double mtml(n,a,b,f)
int n;
double a[],b[],(*f)();
{ int m,i;
double r,s,d,*x;
x=malloc(n*sizeof(double));
www.eeworm.com/read/358056/10196971
c 15topo.c
#include "stdlib.h"
void topo(n,r,m,p)
int n,m,p[],r[];
{ int top,i,j,k,t,*s,*g,*f;
struct node
{ int suc;
int next;
} *q;
q=(struct node *)malloc(m*sizeo
www.eeworm.com/read/358056/10196991
c 13lman.c
#include "stdlib.h"
#include "4rinv.c"
int lman(n,m,k,f,q,r,h,y,x,p,g)
int n,m,k;
double f[],q[],r[],h[],y[],x[],p[],g[];
{ int i,j,kk,ii,l,jj,js;
double *e,*a,*b;
e=mallo
www.eeworm.com/read/356298/10232241
c euler.c
#include "stdio.h"
#include "stdlib.h"
#include
int Func(y,d)
double y[],d[];
{
d[0]=y[1]; /*y0'=y1*/
d[1]=-y[0]; /*y1'=y0*/
d[2]=-y[2]; /*y2'=y2*/
return(1);
}
void E
www.eeworm.com/read/356298/10232247
c grkt10.c
#include "stdio.h"
#include "stdlib.h"
void RKT(t,y,n,h,k,z)
int n; /*微分方程组中方程的个数,也是未知函数的个数*/
int k; /*积分的步数(包括起始点这一步)*/
double t; /*积分的起始点t0*/
double h; /*积分的步长*/
double y[]; /
www.eeworm.com/read/356295/10232261
c dynamic.c
# include
# include
# define NUM 10
int main()
{
char *str[NUM]; /* 定义一个字符性的指针数组 */
int t;
/* 为数组中的每个指针分配内存 */
for(t=0; t