代码搜索:ip核
找到约 10,000 项符合「ip核」的源代码
代码结果 10,000
www.eeworm.com/read/442444/7651679
m ip_02_09.m
% MATLAB script for Illustrative Problem 2.9.
N=1000; % The maximum value of n
M=50;
Rxav=zeros(1,M+1);
Ryav=zeros(1,M+1);
Sxav=zeros(1,M+1);
Syav=zeros(1,M+1);
for i=1:
www.eeworm.com/read/442444/7651681
m ip_02_05.m
% MATLAB script for Illustrative Problem 5, Chapter 2.
echo on
% first part
Sx1=[ones(1,32)];
Rx1=ifft(Sx1,32);
% second part
Sx2=[ones(1,16),zeros(1,224),ones(1,16)];
Rx2=ifft(Sx2,256);
% pl
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m ip_02_04.m
% MATLAB script for Illustrative Problem 2.4.
echo on
N=1000;
M=50;
Rx_av=zeros(1,M+1);
Sx_av=zeros(1,M+1);
for j=1:10, % Take the ensemble average over ten realizations
X=rand(1,N)-1
www.eeworm.com/read/442444/7651686
m ip_02_06.m
% MATLAB script for Illustrative Problem 2.6.
echo on
delta=0.01;
F_min=-2;
F_max=2;
f=F_min:delta:F_max;
Sx=ones(1,length(f));
H=1./(1+(2*pi*f).^2);
Sy=Sx.*H.^2;
www.eeworm.com/read/442444/7651687
m ip_02_08.m
% MATLAB script for Illustrative Problem 2.8.
delta_w=2*pi/100;
w=-pi:delta_w:pi; % one period of Sy
Sy=1./(1.9025-1.9*cos(w));
% Plotting command follows.
plot(w,Sy);
www.eeworm.com/read/442441/7651690
m ip_01_08.m
% MATLAB script for Illustrartive Problem 8, Chapter 1.
ts=0.001;
fs=1/ts;
t=[0:ts:10];
x=cos(2*pi*47*t)+cos(2*pi*219*t)
www.eeworm.com/read/442441/7651691
m ip_01_04.m
% MATLAB script for Illustrative Problem 4, Chapter 1.
echo on
n=[-20:1:20];
% Fourier series coefficients of x(t) vector
x=.5*(sinc(n/2)).^2;
% sampling interval
ts=1/40;
% time vector
t=[-.
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m ip_01_06.m
% MATLAB script for Illustrative Problem 6, Chapter 1
echo on
ts=0.2; % set parameters
fs=1/ts;
df=0.01;
x=[zeros(1,10),[0:0.2:1],ones(1,9),[1:-0.2:0],zeros(1,10)];
[X,x,df1]
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m ip_01_07.m
% MATLAB script for Illustrative Problem 7, Chapter 1.
echo on
df=0.01; % freq. resolution
fs=5; % sampling frequency
ts=1/fs;
www.eeworm.com/read/442441/7651701
m ip_01_03.m
% MATLAB script for Illustrative Problem 3, Chapter 1.
echo on
fnct='normal';
a=-6;
b=6;
n=24;
tol=0.1;
xx=fseries(fnct,a,b,n,tol,0,1);
xx1=xx(n+1:-1:2);
xx1=[conj(xx1),xx];
absxx1=abs(xx1);