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找到约 10,000 项符合「ip核」的源代码

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www.eeworm.com/read/470936/6902052

h ip6_misc.h

/* * Copyright (c) 1993, 1994, 1997 * The Regents of the University of California. All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are
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h ip6_misc.h

/* * Copyright (c) 1993, 1994, 1997 * The Regents of the University of California. All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are
www.eeworm.com/read/467324/7009700

m ip_02_07.m

% MATLAB script for Illustrative Problem 7, Chapter 2. echo on N=256; % number of samples deltaf=0.1; % frequency separation f=[0:deltaf:(N/2)*deltaf, -(N/2-1)*deltaf:deltaf:-deltaf];
www.eeworm.com/read/467324/7009703

m ip_02_08.m

% MATLAB script for Illustrative Problem 8, Chapter 2. delta_w=2*pi/100; w=-pi:delta_w:pi; % one period of Sy Sy=1./(1.9025-1.9*cos(w)); % plotting command follows plot(w,Sy);
www.eeworm.com/read/467324/7009704

m ip_02_03.m

% MATLAB script for Illustrative Problem 3, Chapter 2. echo on rho=0.95; X0=0; N=1000; X=gaus_mar(X0,rho,N); M=50; Rx=Rx_est(X,M); % p
www.eeworm.com/read/467324/7009705

m ip_02_02.m

% MATLAB script for Illustrative Problem 2, Chapter 2. echo on mx=[0 0]'; Cx=[1 1/2;1/2 1]; x=multi_gp(mx,Cx); % Computation of the pdf of (x1,x2) follows delta=0.3; x1=-3:delta:3; x2=-3:delt
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m ip_02_06.m

% MATLAB script for Illustrative Problem 6, Chapter 2. echo on delta=0.01; F_min=-2; F_max=2; f=F_min:delta:F_max; Sx=ones(1:length(f)); H=1./(1+(2*pi*f).^2); Sy=Sx.*H.^2;
www.eeworm.com/read/467324/7009708

m ip_02_04.m

% MATLAB script for Illustrative Problem 4, Chapter 2. echo on N=1000; M=50; Rx_av=zeros(1,M+1); Sx_av=zeros(1,M+1); for j=1:10, % take the ensemble average over 10 realizations X=ran
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m ip_02_05.m

% MATLAB script for Illustrative Problem 5, Chapter 2. echo on % first part Sx1=[ones(1,32)]; Rx1=ifft(Sx1,32); % second part Sx2=[ones(1,16),zeros(1,224),ones(1,16)]; Rx2=ifft(Sx2,256); % pl
www.eeworm.com/read/467324/7009711

m ip_02_09.m

% MATLAB script for Illustrative Problem 9, Chapter 2. N=1000; % The maximum value of n M=50; Rxav=zeros(1,M+1); Ryav=zeros(1,M+1); Sxav=zeros(1,M+1); Syav=zeros(1,M+1); for i