代码搜索:implicit

找到约 5,250 项符合「implicit」的源代码

代码结果 5,250
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f90 dup_save_2.f90

! { dg-do compile } ! { dg-options "-fall-intrinsics -std=f95" } program save_2 implicit none integer i integer foo1, foo2, foo3, foo4 do i=1,10 if (foo1().ne.i) then call abort
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f90 maxlocval_1.f90

! { dg-do run } ! Check that maxval uses for integers HUGE()-1. ! PR fortran/30512 program main implicit none integer(1) :: i1(3), a1(3:2) integer(2) :: i2(3), a2(3:2) integer(4) :: i4(3), a4(3:2) in
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f90 youngs-vof.f90

! calculate the transportation from neighbour cell subroutine transport(c,itype, tanalfa, tanbeta, u1,u3,u4,u2,dx,dy,dt,f1,f3,f4,f2) implicit double precision (a-h,o-z) cotalfa=1.0/tanalfa
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f90 switch_cent.f90

subroutine switch_cent(n1dfft,max2,m2,n2,lot,n1,lzt,zt,zw) implicit real*8 (a-h,o-z) dimension zw(2,lot,n2),zt(2,lzt,n1) ! Here, zero and positive frequencies do
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f svupdn.f

subroutine svupdn(s,haa) implicit none complex*16 s(4), haa(4,4) complex*16 t(4), tmp integer i, j do 100 i=1,4 tmp = dcmplx(0.0d+00,0.0d+00) do 101 j=1,4 tmp = tmp + haa(i,j)*s(j) 101
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f svupdn.f

subroutine svupdn(s,haa) implicit none complex*16 s(4), haa(4,4) complex*16 t(4), tmp integer i, j do 100 i=1,4 tmp = dcmplx(0.0d+00,0.0d+00) do 101 j=1,4 tmp = tmp + haa(i,j)*s(j) 101
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f90 lu.f90

!对矩阵A(N,N)进行LU分解 !无法分解者返回0,成功返回1 FUNCTION DECOMP(A,B,N) IMPLICIT NONE INTEGER R,I,K,N,DECOMP,IMAX,B(N),IP(N) DOUBLE PRECISION FMAX,A(N,N),S,EPS,T(N) PARAMETER(EPS=0.01) DECOMP=1 R=1 DO WHILE(
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f90 ex0435.f90

program ex0435 implicit none ! 判断可以记录9个位数的整数kind值 integer, parameter :: long_int = selected_int_kind( 9 ) ! 判断可以记录3个位数的整数kind值 integer, parameter :: short_int = selected_int_kind( 3 ) ! 判断可以
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f90 adi.f90

SUBROUTINE adi(a,b,c,d,e,f,g,u,jmax,k,alpha,beta,eps) IMPLICIT REAL*8(a-h,o-z) PARAMETER (jj=100,kk=6,nrr=2**(kk-1),maxits=100,& zero=0.d0,two=2.d0,half=0.5d0) DIMENSION a(jmax,jmax),b(
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f90 ex0435.f90

program ex0435 implicit none ! 判断可以记录9个位数的整数kind值 integer, parameter :: long_int = selected_int_kind( 9 ) ! 判断可以记录3个位数的整数kind值 integer, parameter :: short_int = selected_int_kind( 3 ) ! 判断可以