代码搜索:float

找到约 10,000 项符合「float」的源代码

代码结果 10,000
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java mysecond.java

package tr2; public class Mysecond { float op1; float op2; char opr; float result; public void calculate(){ switch (this.opr) { case'+': {this.result=this.op1+this.op2; bre
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c clsq.c

/* ============================================================================ Levenberg-Marquardt Least Squares Optimisation Routine =======================================================
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cpp p50_52test.cpp

const int MaxTerms = 100; class Polynomial; //多项式类的前视声明 class term { //多项式中项的类定义 friend Polynomial; //定义Polynomial类为term类的友元类 private: float coef; //系数 int exp;
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c jm98b.c

/* 98年全国大学生数学建模竞赛B题"水灾巡视问题"模拟退火算法。 这是一个推销员问题,本题有53个点,所有可能性大约为exp(53),目前没有好方法求出精确解,既然求不出精确解,我们使用模拟退火法求出一个较优解,将所有结点编号为1到53,1到53的排列就是系统的结构,结构的变化规则是:从1到53的排列中随机选取一个子排列,将其反转或将其移至另一处,能量E自然是路径总长度。具体算法描述如下: ...
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c show_2d.c

#include void main(void) { int row, column; float table[3][5] = {{1.0, 2.0, 3.0, 4.0, 5.0}, {6.0, 7.0, 8.0, 9.0, 10.0}, {11.0
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c show_3d.c

#include void main(void) { int row, column, table; float values[2][3][5] = { {{1.0, 2.0, 3.0, 4.0, 5.0}, {6.0, 7.0,
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c huge_flt.c

#include #include void main (void) { int i; float huge *values; if ((values = (float huge *) halloc (17000, sizeof(float))) == NULL) printf
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c for_more.c

#include void main () { char letter; float percent; for (letter = 'A'; letter = 'a'; letter--)
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c sizeof.c

#include void main () { printf("Variables of type int use %d bytes\n", sizeof(int)); printf("Variables of type float use %d bytes\n", sizeof(float)); printf("Variables of ty
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c ftest.c

//***************************************************************************** // Filename: ftest.c // Version: 0.01 // Description: test r against rtest (array of n elements) // Returns e