代码搜索:deviation
找到约 1,443 项符合「deviation」的源代码
代码结果 1,443
www.eeworm.com/read/136571/5869638
h portab.h
#ifndef _PORTAB_H_
#define _PORTAB_H_
#if defined(WIN32)
#include
#define DEBUGCBR(A,B,C) { char tmp[100]; wsprintf(tmp, "CBR: frame: %i, quant: %i, deviation: %i\n", (A), (B), (
www.eeworm.com/read/110972/6162174
h portab.h
#ifndef _PORTAB_H_
#define _PORTAB_H_
#if defined(WIN32)
#include
#define DEBUGCBR(A,B,C) { char tmp[100]; wsprintf(tmp, "CBR: frame: %i, quant: %i, deviation: %i\n", (A), (B), (
www.eeworm.com/read/336601/12434803
m smldpe55.m
function [p]=smldPe55(snr_in_dB)
E=1;
SNR=exp(snr_in_dB*log(10)/10); % signal to noise ratio
sgma=E/sqrt(2*SNR); % sigma, standard deviation of noise
N=10000;
% generation of the binar
www.eeworm.com/read/232339/14198037
m rri_multiblock_boot.m
%RRI_MULTIBLOCK_BOOT Apply Behavioral or Task PLS test and bootstrap test
% on RRI scan.
%
% See also PLS_BOOT_TEST, PLS_DEVIATION_BOOT_TEST, BEHAVPLS_BOOT, TASKPLS_BOOT
%
% I (ismean) - 1
www.eeworm.com/read/218391/14922951
m pr3_36.m
%Problem 3.36;
%Simulates the RAKE algorithm on the example of LFM bit pulse.
clear all; close all;
t=[1:3000]/500; N=length(t); %time scale;
WD=40; %deviation of LFM bit pulse;
S=exp(i*pi*WD*(
www.eeworm.com/read/216268/15021388
m pr3_36.m
%Problem 3.36;
%Simulates the RAKE algorithm on the example of LFM bit pulse.
clear all; close all;
t=[1:3000]/500; N=length(t); %time scale;
WD=40; %deviation of LFM bit pulse;
S=exp(i*pi*WD*(
www.eeworm.com/read/14735/405616
h portab.h
#ifndef _PORTAB_H_
#define _PORTAB_H_
#if defined(WIN32)
#include
#define DEBUGCBR(A,B,C) { char tmp[100]; wsprintf(tmp, "CBR: frame: %i, quant: %i, deviation: %i\n", (A), (B), (
www.eeworm.com/read/251805/4416700
h portab.h
#ifndef _PORTAB_H_
#define _PORTAB_H_
#if defined(WIN32)
#include
#define DEBUGCBR(A,B,C) { char tmp[100]; wsprintf(tmp, "CBR: frame: %i, quant: %i, deviation: %i\n", (A), (B), (
www.eeworm.com/read/299916/3849621
m normal.m
function y=normal(x,m,s)
% FUNCTION y=NORMAL(x,m,s)
% Gaussian distribution
% m=mean
% s=standard deviation
y=(1/sqrt(2*pi*s^2))*exp(-((x-m).^2)/(2*s^2));
www.eeworm.com/read/430037/1942710
m pr6_42.m
%Problem 6.42;
%ambiguity function and chart of LFM and VLFM pulses;
clear all; close all;
t=[-1:0.01:1]; N=length(t); %time scale;
WD=25; %frequency deviation in number of 1/T;
S=[exp(i*pi*t.