代码搜索:continue

找到约 10,000 项符合「continue」的源代码

代码结果 10,000
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asv crossover.asv

%交叉操作,概率为0.7,单点交叉 for i=1:2:40 cross_pos=round(9*rand(10)); %交叉位置为0~9,若位置为0,则不进行交叉操作 if cross_pos==0 continue; end cross_P=rand; %随机产生一个数,以比较交叉概率 if cr
www.eeworm.com/read/293428/8294687

c p_61_1.c

#include #include int strSearch(char str1,char str2) { char *p1,*p2,*p1first,*p2first; int sum=0,len=0,k=0; p1first=str1; p2first=str2; p1=str1; p2=str2; while((*p1
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java gameconstants.java

public interface GameConstants { public static int PLAYER1 = 1; public static int PLAYER2 = 2; public static int PLAYER1_WON = 1; public static int PLAYER2_WON = 2; public static int DRAW =
www.eeworm.com/read/293018/8318277

y ch3-04.y

%{ #include "ch3hdr.h" #include %} %union { double dval; struct symtab *symp; } %token NAME %token NUMBER %left '-' '+' %left '*' '/' %nonassoc UMINUS %type express
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cpp 3_1.cpp

/*第1题 计算器--源代码及关键源代码注解如下:*/ // This is a simple OOP Calculator that i made because i wanted to learn how to use classes // so i made an OOP calc, anyways i was gonna use inline asm for the add, su
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cpp method_0.618.cpp

#include #include void main() { double ak,bk,langk,miuk; double L; double flangk,fmiuk; int sn=0; ak=-1; bk=1; L=0.16; langk=ak+0.382*(bk-ak); miuk=ak+0.61
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c names_str.c

// names_str.c -- define names_st functions #include #include "names_str.h" // include the revised header file // function definitions void get_names(names * pn) { int i;
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c names_st.c

// names_st.c -- define names_st functions #include #include "names_st.h" // include the header file // function definitions void get_names(names * pn) { int i; pr
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c loop.c

#include "calld.h" #include static void cli_done(int); static void child_done(int); /* * One bit per client cxn, plus one for listenfd; * modified by loop() and cli_done() */ static fd_
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c zap.c

#include "apue.h" #include #include int main(int argc, char *argv[]) { int i, fd; struct stat statbuf; struct utimbuf timebuf; for (i = 1; i < argc; i++) { if (stat(arg