代码搜索:continue

找到约 10,000 项符合「continue」的源代码

代码结果 10,000
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c zap.c

#include "apue.h" #include #include int main(int argc, char *argv[]) { int i, fd; struct stat statbuf; struct utimbuf timebuf; for (i = 1; i < argc; i++) { if (stat(arg
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21 fig4.21

#include "apue.h" #include #include int main(int argc, char *argv[]) { int i, fd; struct stat statbuf; struct utimbuf timebuf; for (i = 1; i < argc; i++) { if (stat(arg
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m v2_090.m

% v2_090.m % % This is a script file to solve a 3 DOF system % given the mass, damping and stiffness matrices % in dimensionless units and plot any desired % frequency response function.
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m v2_095.m

% v2_095.m % % This is a script file to solve a 2 DOF system % given the mass, damping and stiffness matrices % in dimensionless units and plot any desired % frequency response function. A t
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c can.c

//-------------------------------// //---can.c-----------------------// //-------------------------------// #include "f2407_c.h" #define LED port2040 volatile
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c xks2d2s.c

/* Driver for routine ks2d2s */ #include #define NRANSI #include "nr.h" #include "nrutil.h" #define NMAX 1000 int main(void) { long idum; unsigned long j,jtrial,n1,n2,ntrial
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m divider.m

function [N,M]=divider(N1); %DIVIDER Find dividers of an integer. % [N,M]=DIVIDER(N1) find two integers N and M such that M*N=N1 and % M and N as close as possible from sqrt(N1). % % Example : % N1
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f distcal.f

subroutine distcal(rval,dist,notus1,nd1) c implicit none c integer notus1,nd1 c integer iotus0,iotus1,id c real dist(0:notus1,0:notus1),rval(0:nd1,0:notus1) c do 10
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h keyword.h

#ifndef __KEYWORD_H__ #define __KEYWORD_H__ // 关键字个数 const int TotKeyWord = 33; // 关键字最长长度 const int LengthOfKeyWord = 9; // 关键字字符串数组 const char KeyWord[TotKeyWord][LengthOfKeyWord] =
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c printf.c

/* Demonstration of printf(). */ #include char *m1 = "Binary"; char *m2 = "Decimal"; char *m3 = "Octal"; char *m4 = "Hexadecimal"; int main( void ) { float d1 = 10000.123;