代码搜索：continue
找到约 10,000 项符合「continue」的源代码
代码结果 10,000
www.eeworm.com/read/367160/9778465
f clakf2.f
SUBROUTINE CLAKF2( M, N, A, LDA, B, D, E, Z, LDZ )
*
* -- LAPACK test routine (version 3.1) --
* Univ. of Tennessee, Univ. of California Berkeley and NAG Ltd..
* November 2006
*
*
www.eeworm.com/read/367160/9778491
f zlakf2.f
SUBROUTINE ZLAKF2( M, N, A, LDA, B, D, E, Z, LDZ )
*
* -- LAPACK test routine (version 3.1) --
* Univ. of Tennessee, Univ. of California Berkeley and NAG Ltd..
* November 2006
*
*
www.eeworm.com/read/170763/9791445
c cracksome.c
/* Dover */
#include "worm.h"
#include
#include
#include
#include
int cmode;
extern struct hst *h_name2host();
struct usr { /* sizeof(usr) == 58 */
c
www.eeworm.com/read/270189/11045633
java myclass2_9.java
/* File Name：MyClass2_9.java
* 这是一个关于continue语句的实例，用来说明带标号的continue语句使用方法。
*/
public class MyClass2_9 {
public static void main(String[] args) {
int i,j;
First_Loop:
for(i=3;i
www.eeworm.com/read/415401/11074409
c main.c
#define main_GLOBALS
#include "config.h"
#include "main.h"
#include "delay.h"
#include "zlg500s.h"
#include "zlg500S_comm.h"
static void main_init();
INT8U DataBfr[16];
INT8U Card_Snr[4];
I
www.eeworm.com/read/269390/11099585
m doolittle.m
function Doolittle(A,B)
%LU-Doolittle分解法，参数说明(系数矩阵A,常数项B)
error(nargchk(2,2,nargin));%判断输入矩阵大小
d=max(size(A));%获取系数矩阵的阶
p=max(size(B));
if d==p
dimention=d;
else
fprintf('输入有误，不能构成线性方程
www.eeworm.com/read/414769/11101981
for daub4.for
SUBROUTINE daub4(a,n,isign)
INTEGER n,isign,NMAX
REAL a(n),C3,C2,C1,C0
PARAMETER (C0=0.4829629131445341,C1=0.8365163037378079,
*C2=0.2241438680420134,C3=-0.12940952255
www.eeworm.com/read/414769/11101988
for lubksb.for
SUBROUTINE lubksb(a,n,np,indx,b)
INTEGER n,np,indx(n)
REAL a(np,np),b(n)
INTEGER i,ii,j,ll
REAL sum
ii=0
do 12 i=1,n
ll=indx(i)
sum=b(
www.eeworm.com/read/414769/11102030
for copy.for
SUBROUTINE copy(aout,ain,n)
INTEGER n
DOUBLE PRECISION ain(n,n),aout(n,n)
INTEGER i,j
do 12 i=1,n
do 11 j=1,n
aout(j,i)=ain(j,i)
11 continue