代码搜索：continue
找到约 10,000 项符合「continue」的源代码
代码结果 10,000
www.eeworm.com/read/119523/14827161
cpp pythagorean triples.cpp
#include
#include
int tr[100000][3];//2uv,u^2-v^2,u^2+v^2
//
int gcd(int a,int b)
{
if(b==0)
return a;
return gcd(b,a%b);
}
int abs(int x)
{
if(x>0)
return x;
el
www.eeworm.com/read/218591/14914493
c exit.c
/*
* linux/kernel/exit.c
*
* (C) 1991 Linus Torvalds
*/
#include // 错误号头文件。包含系统中各种出错号。(Linus 从minix 中引进的)
#include // 信号头文件。定义信号符号常量，信号结构以及信号操作函数原型。
#include // 等
www.eeworm.com/read/116901/14950169
java rnd_36_7.java
class rnd_36_7
{
public static void main(String args[])
{
int a[]=new int[7];
for(int i=0;i
www.eeworm.com/read/116603/14962687
java labeledfor.java
//: c03:LabeledFor.java
// From 'Thinking in Java, 2nd ed.' by Bruce Eckel
// www.BruceEckel.com. See copyright notice in CopyRight.txt.
// Java's "labeled for" loop.
public class LabeledFor {
www.eeworm.com/read/216898/14987536
f fidaxpy.f
subroutine fidaxpy(a, x, y, n, iters)
integer i
double precision x(n), y(n), a
double precision b
b = - a
do 2000 j = 1, iters
do 1000 i = 1, n
y(i
www.eeworm.com/read/216703/14996982
cpp mathsubs.cpp
#include "stdafx.h"
//#include "CubSurface.h"
#include "drawcli.h"
#include "math.h"
#include "SideLine.h"
//#define MIN_DISTANCE 10 //最小跨度
/*
判断“点”是否在任意多边形内：
本算法采用射线追踪法：
过待测点
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c ambakbd.c
/* ambaKbd.c - ARM AMBA keyboard driver routines */
/* Copyright 1993-2001 Wind River System, Inc. */
#include "copyright_wrs.h"
/*
modification history
--------------------
01a,06jul01,m_h created
www.eeworm.com/read/212845/15147704
cpp l2test.cpp
/***
*** See the file "mba/disclaimers-and-notices-L2.txt" for
*** information on usage and redistribution of this file,
*** and for a DISCLAIMER OF ALL WARRANTIES.
***/
/* $Id: l2test.cpp,
www.eeworm.com/read/211952/15169889
cpp p1981_物理.cpp
#include
double A , B , C , D;
void PrintAns ( double a , double b , double c )
{
printf ( "%.1lf g of ice and %.1lf g of water at %.1lf C\n" , a , b , c );
}
mai
www.eeworm.com/read/211952/15169959
cpp p2229_比较.cpp
#include
double Ans , V , T;
main ()
{
int N;
while ( scanf ( "%d" , &N ) , N ) {
Ans = 1e30;
for ( int i = 0; i < N; i ++ ) {
sc