代码搜索:complex
找到约 10,000 项符合「complex」的源代码
代码结果 10,000
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cpp cw_fields.cpp
/* Copyright (C) 2006 Massachusetts Institute of Technology.
*
* This program is free software; you can redistribute it and/or modify
* it under the terms of the GNU General Public License as publi
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c rfast21.c
#include
#include
#include
#include
#include "rtdspc.h"
#include "filter.h"
/***********************************************************************
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f e_622_02.f
Complex Function f0(a,b,z)
complex a,b,z
f0=a*z+b*conjg(z)
return
end
c
Complex Function f1(c,d,z)
complex c,d,z
f1=C*(z-1)+d*(conjg(z)-1)+1
return
end
c
Program Complex_map
i
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h ffft.h
#ifndef FFT_N
#define FFT_N 128 /* Number of samples (64,128,256,512). Don't forget to clean! */
//#define INPUT_NOUSE
//#define INPUT_IQ
#ifndef FFFT_ASM /* for c modules */
typedef struc
www.eeworm.com/read/434122/7887782
h ffft.h
#ifndef FFT_N
#define FFT_N 256 /* Number of samples (64,128,256,512). Don't forget to clean! */
//#define INPUT_NOUSE
//#define INPUT_IQ
#ifndef FFFT_ASM /* for c modules */
typedef struc
www.eeworm.com/read/198623/7920486
f dcsin.f
function dcsin(z1)
double complex dcsin, z1, z2
double precision dummy(2), a, b, c, d
equivalence (a,z2,dummy(1)), (b,dummy(2))
z2 = z1
c = dexp(b)
d = 1.0d0/c
b = dcos(a)*(c-d)/2.0d0
a = ds
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f dccos.f
function dccos(z1)
double complex dccos, z1, z2
double precision dummy(2), a, b, c, d
equivalence (a,z2,dummy(1)), (b,dummy(2))
z2 = z1
c = dexp(b)
d = 1.0d0/c
b = dsin(a)*(d-c)/2.0d0
a = dc
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h transform.h
//Transform.h 数学变换头文件
// Ver 1.0.0.0
// 版权所有(C) 何渝, 2002
// 最后修改: 2002.5.31.
#ifndef _TRANSFORM_H //避免多次编译
#define _TRANSFORM_H
#include //模板类输入输出流标准头文件
#include
www.eeworm.com/read/433381/7935137
h transform.h
//Transform.h 数学变换头文件
// Ver 1.0.0.0
// 版权所有(C) 何渝, 2002
// 最后修改: 2002.5.31.
#ifndef _TRANSFORM_H //避免多次编译
#define _TRANSFORM_H
#include //模板类输入输出流标准头文件
#include
www.eeworm.com/read/297981/7982875
cpp fretrans.cpp
#include "stdafx.h"
#include "GlobalApi.h"
#include "Cdib.h"
#include
#include
#include
using namespace std;
// FOURBYTES就是用来计算离4最近的整倍数
#define FOURBYTES(bits