代码搜索:biterror
找到约 49 项符合「biterror」的源代码
代码结果 49
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m biterror.m
% MATLAB SIMULATION OF NSA FS-1016 CELP v3.2
% COPYRIGHT (C) 1995-99 ANDREAS SPANIAS AND TED PAINTER
%
% This Copyright applies only to this particular MATLAB implementation
% of the FS-1016 CELP
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c biterror.c
/**************************************************************************
*
* ROUTINE
* biterror
*
* FUNCTION
*
* introduce random errors in CELP bitstream
*
* SYNOPSIS
*
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sci biterror_f.sci
//BITERROR_f Scicos Bit error Rate calculation block
//Classical interface function ver1.0 - scilab-3.0
//16 novembre 2004 Author : - IRCOM GROUP - A.Layec
function [x,y,typ]=BITERROR_f(job,arg1,a
www.eeworm.com/read/243416/12942649
m performence_with_conv_psk.m
clear all;
N=10;
biterror=0;
biterror_IQ=0;
for i=1:N
[numofbiterror,numofbiterror_IQ]=PSK( 4.1 );
biterror=biterror+numofbiterror
biterror_IQ=biterror_IQ+numofbiterror_IQ
end;
% Pb=biter
www.eeworm.com/read/216822/14991333
asv gmc.asv
clear;
K=8;
P=179;
L=3;
M=16;
J=11;
U=10^5;
sigma=0.0446 ;
%求出R矩阵书上的11页(单位圆上取点),通
R=zeros(M,J);%^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
www.eeworm.com/read/216822/14991334
m gmc.m
clear;
K=8;
P=179;
L=3;
M=16;
J=11;
U=10^5;
sigma=0.0446 ;
%求出R矩阵书上的11页(单位圆上取点),通
R=zeros(M,J);%^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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m gmc.m
clear;
K=8;
P=179;
L=3;
M=16;
J=11;
U=10^4;
sigma=0.03;
%求出R矩阵书上的11页(单位圆上取点),通
R=zeros(M,J);%^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
www.eeworm.com/read/221846/14718361
cpp simulation.cpp
#include
#include
#include
#include
#include
#include "Global.h"
#include "CoDec.h"
#include "Channel.h"
#include "ST.h"
#define ASTEP
www.eeworm.com/read/216822/14991336
m encodegmc.m
clear;
K=8;
P=179;
L=3;
M=16;
J=11;
U=5*10^4;
sigma=0.0629;
%///////////////////////////////////////// Code and decode(include s/p and p/s trans. (use Hamming encode method)
signal=rand
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m encodegmc.m
clear;
K=8;
P=179;
L=3;
M=16;
J=11;
U=10^4;
sigma=0.03;
%///////////////////////////////////////// Code and decode(include s/p and p/s trans. (use Hamming encode method)
signal=randn(1,