代码搜索：binomial
找到约 467 项符合「binomial」的源代码
代码结果 467
www.eeworm.com/read/403922/11500964
html function.stats-cdf-binomial.html
Calculates any one parameter of the binomial distribution given values fo
www.eeworm.com/read/375190/2739347
cpp negative_binomial_example2.cpp
// negative_binomial_example2.cpp
// Copyright Paul A. Bristow 2007.
// Use, modification and distribution are subject to the
// Boost Software License, Version 1.0.
// (See accompanying file LICENS
www.eeworm.com/read/375190/2739352
cpp negative_binomial_example1.cpp
// negative_binomial_example1.cpp
// Copyright Paul A. Bristow 2007.
// Use, modification and distribution are subject to the
// Boost Software License, Version 1.0.
// (See accompanying file LICENS
www.eeworm.com/read/375190/2739366
cpp neg_binomial_sample_sizes.cpp
// neg_binomial_sample_sizes.cpp
// Copyright Paul A. Bristow 2007
// Copyright John Maddock 2006
// Use, modification and distribution are subject to the
// Boost Software License, Version 1.0.
// (
www.eeworm.com/read/375190/2739615
cpp sf_binomial_incl_test.cpp
// Copyright John Maddock 2006.
// Use, modification and distribution are subject to the
// Boost Software License, Version 1.0. (See accompanying file
// LICENSE_1_0.txt or copy at http://www.boo
www.eeworm.com/read/375190/2739625
cpp dist_binomial_incl_test.cpp
// Copyright John Maddock 2006.
// Use, modification and distribution are subject to the
// Boost Software License, Version 1.0. (See accompanying file
// LICENSE_1_0.txt or copy at http://www.boo
www.eeworm.com/read/373627/9445754
index
Functions:
=========
Null Null Spaces of Matrices
addterm Try All One-Term Additions to a Model
anova.negbin Likelihood Ratio Tests for Negative Binomial
www.eeworm.com/read/460181/7256272
m bhp.m
function h = bhp(k)
% h = bhp(k)
% Binomial hipass filter
% H(z) = [(1/z-1)/2]^k
h = 1;
for i = 1:k
h = ([0 h] - [h 0])/2;
end
www.eeworm.com/read/460181/7256273
m blp.m
function h = blp(k)
% h = blp(k)
% Binomial lowpass filter
% H(z) = [(1/z+1)/2]^k
h = 1;
for i = 1:k
h = ([h 0] + [0 h])/2;
end