代码搜索:baseband

找到约 543 项符合「baseband」的源代码

代码结果 543
www.eeworm.com/read/6297/84346

txt baseband.txt

2.3 Channel Control 2.3.1 Controller States Bluetooth controller operates in two major states: Standby and Connection . There are seven substates which are used to add slaves or make connectio
www.eeworm.com/read/289536/3990819

java baseband.java

/*********************************************************************** * Module: BaseBand.java * Author: juny * Created: 2006年7月13日 15:00:31 * Purpose: Defines the Class BaseBand *******
www.eeworm.com/read/415489/2135332

c baseband.c

/* * Copyright (c) 1996, 2003 VIA Networking Technologies, Inc. * All rights reserved. * * This software is copyrighted by and is the sole property of * VIA Networking Technologies, Inc. Thi
www.eeworm.com/read/415489/2135352

h baseband.h

/* * Copyright (c) 1996, 2003 VIA Networking Technologies, Inc. * All rights reserved. * * This software is copyrighted by and is the sole property of * VIA Networking Technologies, Inc. Thi
www.eeworm.com/read/389729/8506478

m digit_baseband.m

clear all; close all; Ts=1; %码元间隔 N_sample=8; %每个码元的抽样点数 dt=Ts/N_sample;%抽样时间间隔 N=1000; %码元数 t=0:dt:(N*N_sample-1)*dt; gt1=ones(1,N_sample); %NRZ非归零波形(NRZ为反向不归零) gt2=ones(1,N_samp
www.eeworm.com/read/430890/8719835

m baseband_pam.m

% Experiment 4, CS: Haykin % Eyediagram % baseband PAM transmission, M=2 % The channel has bandwidth limitations % channel is modeled as low pass butterworth filter % Nyquist bandwidth 0.5Hz, \a
www.eeworm.com/read/355100/10294719

m baseband3.m

% 注意:运行此程序时要先在MATLAB主窗口中输入tutmodce;[t,x,yout] = euler('tutmodce',1); %不然程序会提示缺乏定义的变量 % Sampling frequency fs = 100; % Lowpass filter [num,den] = butter(2,100/2/pi/fs); % DSB-SC AM simulation res
www.eeworm.com/read/482677/6620900

m digit_baseband.m

%数字基带信号的功率谱密度 clear all; close all; Ts=1; N_sample = 8; %每个码元的抽样点数 dt = Ts/N_sample; %抽样时间间隔 N = 1000; %码元数 t = 0:dt:(N*N_sample-1)*dt; T = N*N_sample*
www.eeworm.com/read/409569/11319242

m baseband_dft.m

% baseband OFDM_DFT % close all; clear all; T = 1000; % symbol period f = 1/T; % frequency N = 8; % data No. k = 0:N-1; t = k./N/f; data = floor(rand(1,2*N
www.eeworm.com/read/430890/8719837

m baseband_pam2.m

% Experiment 4, CS: Haykin % Eyediagram % baseband PAM transmission, M=2 % The channel has bandwidth limitations % channel is modeled as low pass butterworth filter % Nyquist bandwidth 0.5Hz, \a