代码搜索：awk
找到约 3,459 项符合「awk」的源代码
代码结果 3,459
www.eeworm.com/read/273665/4201102
awk mksmbpasswd.awk
#!/usr/bin/awk -f
BEGIN {FS=":"
printf("#\n# SMB password file.\n#\n")
}
{ printf( "%s:%s:XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX:XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX:[U ]:LCT-00000000:%s\n", $1, $3,
www.eeworm.com/read/273665/4201187
awk mksmbpasswd.awk
#!/usr/bin/awk -f
BEGIN {FS=":"
printf("#\n# SMB password file.\n#\n")
}
{ printf( "%s:%s:XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX:XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX:[U ]:LCT-00000000:%s\n", $1, $3,
www.eeworm.com/read/448632/1686450
scr awk.scr
/.*\(0x3da.*/||/.*\(0x3ba.*/ {
if (v_3da != 1) print "_v_retrace_";
v_3da = 1;
next;
}
/.*\(0x42.*/||/.*\(0x43.*/ {
if (v_4x != 1) print "_timer_";
www.eeworm.com/read/442570/1758120
scr awk.scr
/.*\(0x3da.*/||/.*\(0x3ba.*/ {
if (v_3da != 1) print "_v_retrace_";
v_3da = 1;
next;
}
/.*\(0x42.*/||/.*\(0x43.*/ {
if (v_4x != 1) print "_timer_";
www.eeworm.com/read/440906/1785535
awk makedoc.awk
# Take apart bits of HTML and puts them back together again in new and
# fascinating ways. Copyright (C) 2002 Free Software Foundation, Inc.
# Contributed by Phil Edwards . Simple t
www.eeworm.com/read/440229/1799052
awk delay.awk
# 使用的是无线trace的旧格式
BEGIN {
highest_packet_id = 0;
}
{
action = $1;
time = $2;
packet_id = $6;
type = $7;
# 不考虑路由包，可以保证序号为0的cbr被统计到
if ( type != "AODV" ) {
i
www.eeworm.com/read/440226/1799147
awk filter.awk
{
if ($1 == "+") {
t = $6
if ($6 == 1000) {
t = 1500
}
print $2, t
}
}
www.eeworm.com/read/440226/1799243
awk seq.awk
BEGIN {
if (dir == "")
dir = ".";
}
{
if ($1 == "-" && ($5 == "tcp" || $5 == "ack")) {
split($9,a,"\.");
saddr = a[1];
sport = a[2];
split($10,a,"\.");
daddr = a[1];
dport = a[2];
if ($5
www.eeworm.com/read/440226/1799244
awk tcp.awk
BEGIN {
if (dir == "")
dir = ".";
}
{
time = $2;
saddr = $4;
sport = $6;
daddr = $8;
dport = $10;
hiack = $14;
cwnd = $18;
ssthresh = $20;
srtt = $26;
rttvar = $28;
ownd = $34;
owndcorr = $36;
nr
www.eeworm.com/read/440226/1799248
awk resptime.awk
{
if (NR > 1)
sum += ($3 - $2);
}
END {
if (NR > 1)
print sum/(NR-1);
else
print -1;
}