代码搜索：average
找到约 5,196 项符合「average」的源代码
代码结果 5,196
www.eeworm.com/read/253260/12235769
cpp block.cpp
// block.cpp -- use a block statement
#include
int main()
{
using namespace std;
cout
www.eeworm.com/read/252908/12255655
java teststudent.java
import mylib.Person;
import mylib.mysublib.Student;
public class TestStudent{
public static void main(String args[]){
Student s1=new Student();
System.out.println("S1:"+s1.toString()+";成绩"+s
www.eeworm.com/read/252063/12304767
c quant.c
/* Copyright (c) Colorado School of Mines, 2003.*/
/* All rights reserved. */
/*********************** self documentation **********************/
/*****************************
www.eeworm.com/read/338439/12307296
txt 解题报告_王波.txt
1002:大数加法。开两个数组，用来存两个加数a,b。如果a>=b,那么加的结果可以放在a里头。反之，则放在b里头。这样可以节约空间。
1003:大数乘法。做法与1002类似。
1005(Move cards):此题带有贪心的算法。从第一堆开始，向后推移。设平均每堆数量为<mark>average</mark>，如果前n堆的数目小于<mark>average</mark>*n，则继续向后推移；否则，如果等于<mark>average</mark>*n，那么则在前n堆里头 ...
www.eeworm.com/read/251889/12313314
java ssq1.java
/* -------------------------------------------------------------------------
* This program simulates a single-server FIFO service node using arrival
* times and service times read from a text file
www.eeworm.com/read/251888/12313469
java ssq1.java
/* -------------------------------------------------------------------------
* This program simulates a single-server FIFO service node using arrival
* times and service times read from a text file
www.eeworm.com/read/251885/12313665
c sis1.c
/* -------------------------------------------------------------------------
* This program simulates a simple (s,S) inventory system using demand read
* from a text file. Backlogging is permitt
www.eeworm.com/read/251885/12313707
c ssq1.c
/* -------------------------------------------------------------------------
* This program simulates a single-server FIFO service node using arrival
* times and service times read from a text file
www.eeworm.com/read/150065/12318967
sas clust7_2.sas
data clus7_2;
infile 'd:clus7_2.dat';
input x1-x16;
proc cluster standard method=average nonorm nosquare ccc pseudo out=tree;
proc tree data=tree horizontal spaces=1;
run;