代码搜索：average
找到约 5,196 项符合「average」的源代码
代码结果 5,196
www.eeworm.com/read/379196/9204833
txt 例9.11.txt
例9.11 静态成员函数的应用。
#include
using namespace std;
class Student //定义Student类
{public:
Student(int n,int a,float s):num(n),age(a),score(s){ } //定义构造函数
void total( )
www.eeworm.com/read/378183/9248011
dat vfpdat47.dat
格式: AVERAGE [][FOR][WHILE][TO |ARRAY]
----
功能: 在打开的表中,对中的各个表达式分别求平均值.
----
www.eeworm.com/read/180892/9281277
c anothertestapp.c
// Description: Driver program that makes use of the average library function
// to compute the average value of a set of integer data values
#include
int main()
{
int tes
www.eeworm.com/read/180892/9281648
c anothertestapp.c
// Description: Driver program that makes use of the average library function
// to compute the average value of a set of integer data values
#include
int main()
{
int test_
www.eeworm.com/read/180601/9301178
c math.c
#include
void main ()
{
int seconds_in_an_hour;
float average;
seconds_in_an_hour = 60 * 60;
average = (5 + 10 + 15 + 20) / 4;
printf("The number of secon
www.eeworm.com/read/180019/9322481
cpp 9_78.cpp
#include
#include
#define Max 20
class English
{
int ptr;
int score[Max];
public:
void getdata(int val,int ptr) {score[ptr]=val;}
int disp(int ptr){return score[ptr
www.eeworm.com/read/376114/9330738
c math.c
#include
void main ()
{
int seconds_in_an_hour;
float average;
seconds_in_an_hour = 60 * 60;
average = (5 + 10 + 15 + 20) / 4;
printf("The number of secon
www.eeworm.com/read/375987/9340483
c filter.c
/**********************************************************************
filter.c file
作者：lig&lij
建立日期：2006-4-25
修改日期：2006-4-25
版本：V1.0
*************************************************
www.eeworm.com/read/375836/9348691
m dispet.m
function dispEt(Tt,Et,Etarget,ert,Kt,Ebsft)
% Et data display method supplied with SA Tools.
% Copyright (c) 2002, by Richard Frost and Frost Concepts.
% See http://www.frostconcepts.com/software f
www.eeworm.com/read/375429/9360221
sql create unique alter table course.sql
use test
alter table course
add aver as dbo.average(cno)