代码搜索:answer

找到约 6,541 项符合「answer」的源代码

代码结果 6,541
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{ X is Answer. Set Cn that Cn*2^n=Xn C(n+1)*2^(n+1) =X(n+1) =Xn+10^n*k, Here k is 1 or 2, namely the first digit of X(n+1) =Cn*2^n+10^n*k => 2*C(n+1)=Cn+5^n*k if Cn is Odd then k=
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