代码搜索:answer

找到约 6,541 项符合「answer」的源代码

代码结果 6,541
www.eeworm.com/read/419318/10875271

txt winners v.s. losers.txt

WINNERs LOSERs ------------------------------------------------------------------ It may be difficult, It may be possible, It is POSSIBLE
www.eeworm.com/read/348596/10881746

txt 1436.txt

#include"iostream.h" #include"memory.h" #include"algorithm" using namespace std; int y1[8000],y2[8000],x[8000],index[8000]; int l[16000],n; int *edge[8000]; int cmp(int a,int b) {retur
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txt 1977.txt

#include"iostream.h" #include"string.h" char m[30][100][100]; int n,t,v[100]; char name[100][100][100]; char nm[100][100]; int s[100]; char ans[100][100]; char temp[100][100]; void mult
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txt 1318.txt

#include"iostream.h" inline int same(char *p1,char *p2) {int n,i=0,j=0,*t1,*t2; while(p1[i]!=0)i++; while(p2[j]!=0)j++; n=j; if(i!=j)return 0; t1=new int[256]; t2=new int[256]; for(i=
www.eeworm.com/read/348596/10881855

txt 1947.txt

#include #include using namespace std; list< int > e[150]; int ans[150][151]; int n, p, answer; int root; int creat( int r ) { int i, j, n, m, c, temp[151]; n = 1;
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txt 2428.txt

#include"iostream.h" #include"stdio.h" #include"math.h" struct point { double x,y,z; }p1[110],p2[110],p3[110]; int n,m; double best[110][110]; double cross(point a,point b,point c)
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txt 3082.txt

Source Problem Id:3082 User Id:fzk Memory:1564K Time:171MS Language:Java Result:Accepted Source import java.util.*; class point { int x,y; point(){x=y=0;} }; public class M
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txt 1133.txt

//精度; //find(); 二分查找可以改进 #include"iostream.h" #include"math.h" #include #include using namespace std; struct point {long x,y;}; typedef point vect; struct {point
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txt 1432.txt

#include"iostream.h" #include"memory.h" #include"string.h" char ma[][5]={".-","-...","-.-.","-..",".","..-.","--.","....", "..",".---","-.-",".-..","--","-.","---",".--.", "--.-",".-.
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txt 1186.txt

#include"iostream.h" #include"memory.h" const long prime=3111011; const long big=2147483647; long answer; long hash[prime]; int num[prime]; long mi[151][32]; long find(long m) {long