代码搜索：alloc
找到约 10,000 项符合「alloc」的源代码
代码结果 10,000
www.eeworm.com/read/460969/7236493
f90 alloc_wavefield.f90
!=======================================================================
SUBROUTINE ALLOC_WAVEFIELD
USE PRECISION , ONLY: WP
USE CONTROL_DATA, ONLY: MZ, MR, NRFREQ
USE WAVEFIELD , ONLY:
www.eeworm.com/read/460969/7236498
f90 alloc_nr.f90
!=======================================================================
SUBROUTINE ALLOC_NR
USE PRECISION , ONLY: WP
USE CONTROL_DATA, ONLY: MZ
USE NONREF_BOUND, ONLY: NR_DATA_Z, SZ_D
www.eeworm.com/read/459177/7278946
doc sgi-stl-alloc.doc
www.eeworm.com/read/441677/7667182
h pm-alloc-local.h
//pallas/drv/os/pm-alloc-local.h
/*----------------------------------------------------------------------------+
|
| This source code has been made available to you by IBM on an AS-IS
| ba
www.eeworm.com/read/441677/7667186
c pm-alloc-test.c
//pallas/drv/os/test/pm-alloc-test.c
/*----------------------------------------------------------------------------+
|
| This source code has been made available to you by IBM on an AS-IS
|
www.eeworm.com/read/199007/7895034
doc sgi-stl-alloc.doc
www.eeworm.com/read/327775/13062190
asv optimal_pow_alloc.asv
%输入参数：aa为信道状态信息，是信道增益模值的平方除以噪声功率,是行向量，维数为K
%K为子信道个数，M为调制阶数（你主要以什么调制为主就用哪个，譬如16QAM,那么M=16)
function power_alloc=optimal_pow_alloc(aa,K,M)
M=4;
a=2*(sqrt(M)-1)/(sqrt(M)*log2(sqrt(M)));
b=3/(M-1);
www.eeworm.com/read/327775/13062204
m optimal_pow_alloc.m
%输入参数：aa,K,其中aa为信道状态信息，是信道增益模值的平方除以噪声功率,是行向量，维数为K
%K为子信道个数
%输出：各个子信道上应分配的功率,也是一个1xK的行向量，与信道状态信息是对应的
function power_alloc=optimal_pow_alloc(aa,K)
M=4;
a=2*(sqrt(M)-1)/(sqrt(M)*log2(sqrt(M)));
b=3
www.eeworm.com/read/327775/13062225
asv optimal_pow_alloc.asv
%输入参数：aa为信道状态信息，是信道增益模值的平方除以噪声功率,是行向量，维数为K
%K为子信道个数，M为调制阶数（你主要以什么调制为主就用哪个，譬如16QAM,那么M=16)
function power_alloc=optimal_pow_alloc(aa,K,M)
M=4;
a=2*(sqrt(M)-1)/(sqrt(M)*log2(sqrt(M)));
b=3/(M-1);
www.eeworm.com/read/327775/13062241
m optimal_pow_alloc.m
%输入参数：aa,K,其中aa为信道状态信息，是信道增益模值的平方除以噪声功率,是行向量，维数为K
%K为子信道个数
%输出：各个子信道上应分配的功率,也是一个1xK的行向量，与信道状态信息是对应的
function power_alloc=optimal_pow_alloc(aa,K)
M=4;
a=2*(sqrt(M)-1)/(sqrt(M)*log2(sqrt(M)));
b=3