代码搜索：Zigzag
找到约 281 项符合「Zigzag」的源代码
代码结果 281
www.eeworm.com/read/286908/8737889
c~ zigzag.c~
/*---------------------------------------------------------------------------
* Arnold transformation
* ---------------------------------------------------------------------------*/
#include
www.eeworm.com/read/286908/8737905
c zigzag.c
/*---------------------------------------------------------------------------
* zigzag transformation
* ---------------------------------------------------------------------------*/
#include
www.eeworm.com/read/430125/8765045
m zigzag.m
function Z = Zigzag(S);
%Zigzag表
ZT=[0 ,1 ,5 ,6 ,14,15,27,28;
2 ,4 ,7 ,13,16,26,29,42;
3 ,8 ,12,17,25,30,41,43;
9 ,11,18,24,31,40,44,53;
10,19,23,32,39,45,52,54;
20,22,33,38,46,5
www.eeworm.com/read/282743/9070534
v zigzag.v
/////////////////////////////////////////////////////////////////////
//// ////
//// Zig-Zag Unit
www.eeworm.com/read/282438/9093534
h zigzag.h
/*****************************************************************************
*
* XVID MPEG-4 VIDEO CODEC
* - ZigZag order matrices -
*
* Copyright(C) 2001-2002 Michael Militzer
www.eeworm.com/read/167475/9967954
jpg zigzag.jpg
www.eeworm.com/read/164875/10084272
m zigzag.m
function out=zigzag(in,action)
%采用对称法；
%原始矩阵必须是(2^n)*(2^n)的方阵；
%如果action的值为0，表示zigzag正向扫描；如果action的值为1表示zigzag反向扫描。
if nargin
www.eeworm.com/read/359689/10129917
c zigzag.c
#include "dct.h"
extern short block[BLOCK_SIZE];
void zigzag(void)
{
int i;
short zig[BLOCK_SIZE];
zig[0] = block[0];
zig[1] = block[1];
zig[2] = block[8];
zig[3] = block[16];
www.eeworm.com/read/424027/10505994
m zigzag.m
function q=zigzag(in)
%zigzag扫描函数
%% 函数体
[n,m]=size(in);
if( (n~=8) & (m~=8))
error('输入不是 8*8 矩阵格式');
end
zig = [ 0, 1, 8, 16, 9, 2, 3, 10, ... %按图写出下边排列顺序，下标从0开始
17, 2