代码搜索:ZJU
找到约 171 项符合「ZJU」的源代码
代码结果 171
www.eeworm.com/read/139501/13153216
jpg zju.jpg
www.eeworm.com/read/282031/9123393
cpp zju1003.cpp
#include
#include
using namespace std;
const int MAX = 100;
bool UsedBalloon[MAX+1];
//first run CanFactor(1,b)
bool CanFactor(int i, int b)
{
if (b == 1)
www.eeworm.com/read/281473/9154203
cpp zju1160.cpp
//: ZJU1160.CPP
/* Biorhythms
http://acm.zju.edu.cn/show_problem.php?pid=1160
--------------------------------------------------------------------------------
Time limit: 10 Seconds Memory limit
www.eeworm.com/read/406240/11446560
cpp zju1949.cpp
#include
#include
int a[100][100];
int findrow(int a[][100],int n)
{
int sum=0;
int wrong=0,wrow;
int i,j;
for(i=1;i
www.eeworm.com/read/406240/11446567
cpp zju1021.cpp
#include
int main()
{
int a[51]={0};
int output[51]={0};
int n;
int i,j;
char symbol;
int num=0;
scanf("%d",&n);
while(n!=0)
{
fflush(stdin);
scanf("%c",&symbol);
www.eeworm.com/read/406240/11446568
cpp zju1049.cpp
#include
#include
#define pai 3.1415926
int main()
{
int n;
int i;
float a,b;
float area;
int year;
scanf("%d",&n);
for(i=1;i
www.eeworm.com/read/406240/11446569
cpp zju1205.cpp
www.eeworm.com/read/406240/11446570
cpp zju1115.cpp
#include
int root=0;
void diroot(int n)
{
int i=0,j;
long int k=n;
long int sum=0;
int a[20]={0};
while(k>=10)
{
a[i]=k%10;
k=(k-a[i])/10;
i++;
}
a[i]=k;
for(j
www.eeworm.com/read/406240/11446571
cpp zju1067.cpp
#include
int color[16][3];
int pow(int n,int m)
{
int i,k=1;
for(i=1;i
www.eeworm.com/read/339551/12225999
cpp zju_2419.cpp
/*
凸包( Convex Hull )
凸包是对平面是上的某个点集而言的,凸包是一个最小凸多边形,满足点集
中的所有点都在该凸多边形内(或在该多边形的边上)。
通常,我们采用Graham扫描法来求点集的凸包。首先,排序选出点集中最左下
角点(先取y坐标最小的点,若有多个再在其中取x坐标最小的点),设该点为p0;
然后,将其余的按以p0为中心的极角坐标逆时针排序,多于相同极角的点只保留 ...