代码搜索：Variance
找到约 2,271 项符合「Variance」的源代码
代码结果 2,271
www.eeworm.com/read/244597/12853970
cpp xtutest.cpp
#include
#include
#include
#include "nr.h"
using namespace std;
// Driver for routine tutest
int main(void)
{
const int NPTS=5000,MPTS=1000,NSHFT=10;
www.eeworm.com/read/244076/12891023
c report.c
/*
* GENESIS Copyright (c) 1986, 1990 by John J. Grefenstette
* This program may be freely copied for educational
* and research purposes. All other rights reserved.
*
* file: report
www.eeworm.com/read/140665/13068674
cpp xtutest.cpp
#include
#include
#include
#include "nr.h"
using namespace std;
// Driver for routine tutest
int main(void)
{
const int NPTS=5000,MPTS=1000,NSHFT=10;
www.eeworm.com/read/238965/13312668
m fig9_28.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurement vector H=[1,0,0]
% this is the
www.eeworm.com/read/238965/13312767
m fig9_27.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2);% + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurmeny vector H=[1,0,0]
% this is the
www.eeworm.com/read/137229/13337870
c report.c
/*
* GENESIS Copyright (c) 1986, 1990 by John J. Grefenstette
* This program may be freely copied for educational
* and research purposes. All other rights reserved.
*
* file: report
www.eeworm.com/read/137160/13341862
m pcaklm.m
%PCAKLM Principal Component Analysis/Karhunen-Loeve Mapping
% (PCA or MCA of overall/mean covariance matrix)
%
% [W,FRAC] = PCAKLM(TYPE,A,N)
% [W,N] = PCAKLM(TYPE,A,FRAC)
%
% INPUT
% A
www.eeworm.com/read/137160/13342604
m klm.m
%KLM Karhunen-Loeve Mapping (PCA or MCA of mean covariance matrix)
%
% [W,FRAC] = KLM(A,N)
% [W,N] = KLM(A,FRAC)
%
% INPUT
% A Dataset
% N or FRAC Number of dimensions (>= 1) or fr
www.eeworm.com/read/321424/13405159
m fig9_28.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurement vector H=[1,0,0]
% this is the
www.eeworm.com/read/321424/13405200
m fig9_27.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2);% + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurmeny vector H=[1,0,0]
% this is the