代码搜索：Variance
找到约 2,271 项符合「Variance」的源代码
代码结果 2,271
www.eeworm.com/read/167781/9952880
m program_09_4.m
% Program 9_4
% Computation of the output noise variance due
% to input quantization of a digital filter
% based on a partial-fraction approach
%
num = input('Type in the numerator = ');
den
www.eeworm.com/read/362500/9995891
m gscale.m
function [gx,mx,stdx] = gscale(x)
%GSCALE group scales a matrix.
% GSCALE scales an input matrix (x) such that the columns
% have mean zero and variance relative to the total
% variance in (x).
www.eeworm.com/read/362500/9995897
m varcap.m
function vc = varcap(x,loads,scl,plots);
%VARCAP Variance captured for each variable in PCA model
% Calculates percent variance captured in a PCA model for each
% variable and number of PCs. Inpu
www.eeworm.com/read/166114/10035444
m bootstrap.m
function [x,q] = bootstrap(actualx,y,R,Q,initVar,numSamples);
% PURPOSE : This m file performs the bootstrap algorithm (a.k.a. SIR,
% particle filter, etc.) for the model specified in the
%
www.eeworm.com/read/165851/10049148
m program_09_4.m
% Program 9_4
% Computation of the output noise variance due
% to input quantization of a digital filter
% based on a partial-fraction approach
%
num = input('Type in the numerator = ');
den
www.eeworm.com/read/163777/10145956
m program_9_4.m
% Program 9_4
% Computation of the output noise variance due
% to input quantization of a digital filter
% based on a partial-fraction approach
%
num = input('Type in the numerator = ');
den
www.eeworm.com/read/358502/10186291
mdl koe_channel_awgn.mdl
Model {
Name "koe_channel_awgn"
Version 3.00
SimParamPage "Solver"
SampleTimeColors off
InvariantConstants off
WideVectorLines off
ShowLineWidths off
ShowPortDataType
www.eeworm.com/read/356723/10222105
m fig11_27.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2);% + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurmeny vector H=[1,0,0]
% this is the
www.eeworm.com/read/356723/10222107
m fig11_28.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurmeny vector H=[1,0,0]
% this is the u
www.eeworm.com/read/356183/10235308
m fig9_28.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurement vector H=[1,0,0]
% this is the