代码搜索结果
找到约 10,000 项符合
Switch 的代码
codetc8.dat
<mark>switch</mark> 语句
功能:<mark>switch</mark>语句是多分支选择语句.用来实现多分支选择结构.if语句只有两个分支可供选择,而实际问题中常常要用到多分支的选择.例如,学生成绩分类(90为"A"等,80-89分为'B'等,70-90分为'C'等......).当然这些都可以用嵌套的if语句来外理,但如果分支较多,则嵌套的if语句层数多,程序沉余长而且可读性降低.C语言提供<mark>switch</mark>语句直接外理多分支 ...
keysquar1.lst
C51 COMPILER V8.08 KEYSQUAR1 12/16/2008 10:24:03 PAGE 1
C51 COMPILER V8.08, COMPILATION OF MODULE KEYSQUAR1
OBJECT MODULE PLACED
about_d_lock.txt
功能分析:
1:使用普通用户编号和密码进入
流程:
main()
{init();
while(1)
{ getkey();
switch(选择操作)
{case 进入 in 程序
case 超级用户登录,admini程序
}
}
}
数
guicallback.m
vda = get(da,'Value');
vdm = get(dm,'Value');
vmm = get(mm,'Value');
switch vda
case 1
cda = 'C';
case 2
cda = 'F';
case 3
cda = 'S';
case 4
cda = 'FS';
otherwise
error('Unknown actua
horse.c
#define HORSE_C
#include "includes.h"
void horse(unsigned char i)
{
switch(i)
{
case 0:
OutPort = 0x00;
break;
case 1:
OutPort =
horse.c
#define HORSE_C
#include "includes.h"
void horse(unsigned char i)
{
switch(i)
{
case 0:
OutPort = 0x00;
break;
case 1:
OutPort =
vowels.c
#include
void main()
{
char letter;
int vowel_count = 0;
for (letter = 'A'; letter
display.h
#ifndef __display_H__
#define __display_H__
void display(unsigned char number,unsigned char position)
{
P0=0xff;
switch(position)
{
case 1:{P0=P0&0xf8;break;}
case 2:{P0=P0&0xf9
run_draw.m
function Run_Draw(Fig_UserData,isYnHold)
%创建一个函数对应绘图函数实现的功能
%Fig_UserData为输入参数,对应于Figure的属性'UserData'的值'
%isYnHold为hold on和hold off的判断位
if length(Fig_UserData)~=7
ErrorDlg('输入参量不符合长度要求');
expect.pl
use Expect;
use strict;
use warnings;
sub readdata{
open(FILEHANDLE,"switch.txt")||die"can not open filename:$!";
my(@array)=;
chomp@array;
close(FILEHANDLE);
return(@array);
}