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找到约 10,000 项符合 Switch 的代码

codetc8.dat

<mark>switch</mark> 语句 功能:<mark>switch</mark>语句是多分支选择语句.用来实现多分支选择结构.if语句只有两个分支可供选择,而实际问题中常常要用到多分支的选择.例如,学生成绩分类(90为"A"等,80-89分为'B'等,70-90分为'C'等......).当然这些都可以用嵌套的if语句来外理,但如果分支较多,则嵌套的if语句层数多,程序沉余长而且可读性降低.C语言提供<mark>switch</mark>语句直接外理多分支 ...

keysquar1.lst

C51 COMPILER V8.08 KEYSQUAR1 12/16/2008 10:24:03 PAGE 1 C51 COMPILER V8.08, COMPILATION OF MODULE KEYSQUAR1 OBJECT MODULE PLACED

about_d_lock.txt

功能分析: 1:使用普通用户编号和密码进入 流程: main() {init(); while(1) { getkey(); switch(选择操作) {case 进入 in 程序 case 超级用户登录,admini程序 } } } 数

guicallback.m

vda = get(da,'Value'); vdm = get(dm,'Value'); vmm = get(mm,'Value'); switch vda case 1 cda = 'C'; case 2 cda = 'F'; case 3 cda = 'S'; case 4 cda = 'FS'; otherwise error('Unknown actua

horse.c

#define HORSE_C #include "includes.h" void horse(unsigned char i) { switch(i) { case 0: OutPort = 0x00; break; case 1: OutPort =

horse.c

#define HORSE_C #include "includes.h" void horse(unsigned char i) { switch(i) { case 0: OutPort = 0x00; break; case 1: OutPort =

vowels.c

#include void main() { char letter; int vowel_count = 0; for (letter = 'A'; letter

display.h

#ifndef __display_H__ #define __display_H__ void display(unsigned char number,unsigned char position) { P0=0xff; switch(position) { case 1:{P0=P0&0xf8;break;} case 2:{P0=P0&0xf9

run_draw.m

function Run_Draw(Fig_UserData,isYnHold) %创建一个函数对应绘图函数实现的功能 %Fig_UserData为输入参数,对应于Figure的属性'UserData'的值' %isYnHold为hold on和hold off的判断位 if length(Fig_UserData)~=7 ErrorDlg('输入参量不符合长度要求');

expect.pl

use Expect; use strict; use warnings; sub readdata{ open(FILEHANDLE,"switch.txt")||die"can not open filename:$!"; my(@array)=; chomp@array; close(FILEHANDLE); return(@array); }