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找到约 10,000 项符合 Switch 的代码

hex5509.cmd

lcd.out -map lcd.mxp -o lcd.hex -m2 -v5510:1 -boot -emif32 ROMS { PAGE 0 : ROM : o=0x400000, l=0x100000 } /* SECTIONS { .vectors boot .stack boot .text

motccdef.asm

;********************************************************************** ; ; MOTCC.ASM - 29/01/2002 ; ;********************************************************************** ;*******************

system.h.txt

any problems, send mails to sindybear@163.com 相关文件 这是最为重要的一个宏,经过它以后,进程就经过了切换。 #define switch_to(prev,next,last) do { \ asm volatile("pushl %%esi\n\t" //这是参数的位置(规定) "pushl %%ed

power.c

/*++ Copyright (c) 1996 Microsoft Corporation Module Name: power.c Abstract: NULL filter driver -- boilerplate code Author: ervinp Environment: Kernel mode Revi

2_5a.c

/* ======================================== */ /* 程式实例: 2_5a.c */ /* 查询上课的课目,其中课程以代码表示. */ /* 0 表示没课 */ /* 1 表示计算机概论

al4_7.c

/*案例代码文件名:AL4_7.C。*/ /*功能:已知利润求薪水。*/ main() { long profit; int grade; float salary=500; printf("Input profit: "); scanf("%ld", &profit); grade= (profit – 1) / 1000; /* 将利润-1、再整

abstract.txt

This example program shows how to use RTX51 Tiny in Code Banking Applications. The system contains 4 tasks and is very similar to the RTX51 Tiny Example EX2. However, the system avoids Round-R

ch5_7.c

/*ch5_7*/ #include main() { long profit; int grade; float salary=500; printf("Input profit: "); scanf("%ld", &profit); grade= (profit - 1) / 1000;

4-11.c

main() { long profit; int grade; float salary=500; printf("Input profit: "); scanf("%ld", &profit); grade= (profit – 1) / 1000; /*将利润-1、再整除1000,转化成 switch语句中的cas

hc456.m

%《数字信号处理教程——MATLAB释义与实现》第四章例4.5.6程序hc456 % T,N,L变化时频点集的对应关系 % 电子工业出版社出版 陈怀琛编著 2004年9月 % T0=[0.1,0.05,0.05,0.1]; N0=[16,16,32,32]; for r=1:4 T=T0(r);N=N0(r); % 设定T和N的