代码搜索:Solve

找到约 3,477 项符合「Solve」的源代码

代码结果 3,477
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m solve.m

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m solve.m

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c solve.c

#include "cbox11.h" /*[function Solve : Solution of the linear systems of equations by the Gauss elimination method providing for interchanging rows when encountering a zero diagonal coeficient. A
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c solve.c

#include "cbox5.h" /*[ function Solve : Solution of the linear systems of equations by the Gauss elimination method providing for interchanging rows when encountering a zero diagonal coeficient. A
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c solve.c

#include "cbox2.h" /*[function Solve : Solution of the linear systems of equations by the Gauss elimination method providing for interchanging rows when encountering a zero diagonal coeficient. A :
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c solve.c

#include "cbox1.h" /*[function Solve for the solution of a linear system of equations by the Gauss Elimination method providing for interchange of rows when a zero diagonal coeficient is encountered.
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m solve.m

function varargout = solve(varargin) %求各种类型方程组的解析解, %当找不到解析解时,将自动寻求原点附近的一个近似解, 并可达任意精度. %用法 % solve('方程1','方程2',...,'方程N','变量1','变量2',...,'变量M') %SOLVE Symbolic solution of algebraic equation
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java solve.java

import javax.swing.JOptionPane; class Solve{ int a[]={57,71,87,97,99,101,103,113,114,115,128,129,131,137,147,156,163,186}; int b[] =new int[18];//保存与a[]对应的原子量个数 int x; //待分解的数 int n=0; /
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txt solve.txt

4 3 1 0 2 0 3 2 1 4 3 4 1 2 0 0 1 3 2 4 1 0 4 2 3 3 2 0 4 1 1 0 4 2 3 1 4 0 2 3 3 4 0 2 1 4 0 1 2 3 1次迭代最短路程:11.4049 2 3 0 4 1 4 2 0 1 3 0 1 3 4 2 4 2 1 0 3 3 4 1 2 0 1
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txt solve.txt

4 2 1 3 0 1 2 4 0 3 2 1 0 4 3 1 2 4 0 3 1 4 2 3 0 0 1 3 2 4 3 2 1 0 4 3 4 0 1 2 4 1 2 3 0 4 0 2 3 1 1次迭代最短路程:11.4049 0 1 2 4 3 3 4 0 1 2 3 4 0 1 2 3 4 0 1 2 0 4 3 2 1 4