代码搜索：Signals
找到约 6,227 项符合「Signals」的源代码
代码结果 6,227
www.eeworm.com/read/411369/11248102
m sampenc_data.m
close all;
clear all;
clc
load('original signals.mat');
for q=1:27
y_wear=wear(q,:);
y_sharp=sharp(q,:);
zz=hmapdn(y_sharp);
zzz=hmapdn(y_wear);
m=2;
r=0.1;
for i=1:13
aa=zz(i,:,:);
aa=aa
www.eeworm.com/read/411369/11248105
asv sampenc_data.asv
close all;
clear all;
clc
load('original signals.mat');
for q=1:27
y_wear=wear(q,:);
y_sharp=sharp(q,:);
zz=hmapdn(y_sharp);
zzz=hmapdn(y_wear);
m=2;
r=0.1;
for i=1:13
aa=zz(i,:,:);
aa=aa
www.eeworm.com/read/190387/8444195
m ica.m
% The time period of the signal considered
Tf=0.5;
% The sampling time period
Ts=1e-5;
t=0:Ts:Tf;
Num_iter=100000;
% The source signals
u1=0.1*sin(400*t).*cos(30*t);
u2=0.01*sign(sin(500*t+9*cos(4
www.eeworm.com/read/381211/9103865
m fg_08_14.m
% fg_08_14 Signals f and g for system identification demo.
K=64;
randn('seed',0);
f=randn(1,K);
c=exp(-.1);
d=filter([0 c*sin(.1*pi)], [1 -2*c*cos(.1*pi) c^2], f);
sp_fig(1,9,5.5);
subplot
www.eeworm.com/read/168045/9941022
m ica.m
% The time period of the signal considered
Tf=0.5;
% The sampling time period
Ts=1e-5;
t=0:Ts:Tf;
Num_iter=100000;
% The source signals
u1=0.1*sin(400*t).*cos(30*t);
u2=0.01*sign(sin(500*t+9*cos(4
www.eeworm.com/read/420106/10816580
m sigplot2win_s.m
function [sys,x0,str,ts] = sigplot2win_s(t,x,u,flag, restParams)
%SIGPLOT2WIN_S S-function for plotting radar signals.
%
%--------
%Synopsis:
% [sys,x0,str,ts] = sigplot2win_s(t,x,u,flag, restParams
www.eeworm.com/read/437052/7755845
m crossspectra.m
function [cs,f] = CrossSpectra(x1,x2,fsa,wla,ola,fra,pfa)
%CrossSpectra: Computes the cross-spectra of two signals.
%
% [cs,f] = CrossSpectra(x1,x2,fs,wl,ol,fr,pf)
%
% x1 Input Signal
% x2 I
www.eeworm.com/read/437052/7755847
m coherency.m
function [c,f] = Coherency(x1,x2,fsa,wla,sna,ola,nfa,pfa)
%Coherency: Computes the estimated coherence of two signals.
%
% [c,f] = Coherency(x1,x2,fs,wl,sn,ol,nf,pf)
%
% x1 Input Signal
% x2
www.eeworm.com/read/398034/8009001
m sa_ex7_9b.m
% Min-Norm AOA estimation for a M = 6 element array with noise variance = .1
M=6;
D = 2; % number of signals
sig2=.1;
th1=-5*pi/180;
th2=5*pi/180;
a1=[1];
a2=[1];
a=[1];
temp=zeros(1,M-1
www.eeworm.com/read/398034/8009015
m sa_ex7_10.m
% Min-Norm AOA estimation for a M = 6 element array with noise variance = .1
tic
M=6;
D = 2; % number of signals
sig2=.1;
th1=-5*pi/180;
th2=5*pi/180;
a1=[1];
a2=[1];
a=[1];
F=[1;1];
tem