代码搜索:Sign

找到约 10,000 项符合「Sign」的源代码

代码结果 10,000
www.eeworm.com/read/282801/9059786

cpp 哈夫曼编码.cpp

#define INT_MAX 10000 #define ENCODING_LENGTH 1000 #include "stdio.h" #include "string.h" #include "malloc.h" typedef enum{none,left_child,right_child}Which;//标记是左孩子还是右孩子 typedef char Elemtype;/
www.eeworm.com/read/381951/9062030

cpp extremumgold1d.cpp

//ExtremumGold1D.CPP 黄金分割法求一维函数极值 #include //模板类iostream输入输出流标准头文件 #include "Extremum.h" //极值头文件 using namespace std; //名字空间 void main() { double fextremum,ax,bx,cx,fa,fb,fc,
www.eeworm.com/read/380755/9129720

m crc decode.m

% 采用美国16-CRC标准 % 16bit CRC 生成多项式D16+D1+D2+1 % 输入code为要进行解码的码源 % 返回值sign是指示是否出现错误1为有错,0为无错 % 如果正确 指示0 并解码,decode 为解码后的码 function [decode] =CrcDecode(code) generator = [1 0 0 0 0 0 1 0 0 0 1 1 1 0
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m crcdecode.m

% 采用美国16-CRC标准 % 16bit CRC 生成多项式D16+D1+D2+1 % 输入code为要进行解码的码源 % 返回值sign是指示是否出现错误1为有错,0为无错 % 如果正确 指示0 并解码,decode 为解码后的码 function [decode] =CrcDecode(code) generator = [1 0 0 0 0 0 1 0 0 0 1 1 1 0
www.eeworm.com/read/380446/9149250

cpp extremumgold1d.cpp

//ExtremumGold1D.CPP 黄金分割法求一维函数极值 #include //模板类iostream输入输出流标准头文件 #include "Extremum.h" //极值头文件 using namespace std; //名字空间 void main() { double fextremum,ax,bx,cx,fa,fb,fc,
www.eeworm.com/read/380443/9149561

h dct.h

#ifndef __DCT #define __DCT #include "pi.h" #define BLOCKSIZE 50 #define MAX_NUM_ROWS 2050 void FastCosineTransform(float *array, int xsize, int ysize, int sign);
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m ex_3.m

%例4 clear all syms t f=maple('heaviside(t+3)-2*heaviside(t)'); t1=-5:0.01:5; ff=subs(f,t,t1); figure(1) plot(t1,ff),axis([-5,5,-1.2,1.2]),title('u(t+3)-2u(t)') t=-5:0.01:5; f=heaviside(t+3)-2
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m outsideconvex.m

function i=outsideConvex(x,n,o,tol) % function i=outsideConvex(x,n,o,tol). Determine which points are outside % the convex object described by n'*x+o
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m valve_motor_pinion.m

%valve_moter_pinion.m %differential equation function dxdt=valve_motor_pinion(t,x) %dxdt=zeros(8,1); %x=zeros(8,1); %ui=zeros(4,1); ui=[10;-10;10;-10]; %------------------------ i1=44.8; i2=4
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asv valve_motor_pinion.asv

%valve_moter_pinion.m %differention equation function dxdt=valve_motor_pinion(t,x,ui) i1=44.8; i2=4.21; %--------------------油路1的参数 Jm1=200;%马达的转动惯量 Ip1=4000;%小齿轮的转动惯量 Je1=Jm1*i1+Ip1*i2;%等效惯量