代码搜索：Sign
找到约 10,000 项符合「Sign」的源代码
代码结果 10,000
www.eeworm.com/read/419010/10889525
asm example 2-28.asm
;Example 2 - 28. Float-Point Addition ASM Listing for TMS320C54x
;/* ============================================================================*/
;/* Copyright (C) 2004 YINXING TECHN
www.eeworm.com/read/273416/10916653
java signfunction.java
public class SignFunction{
public static void main(String args[]) {
int intx;
intx=0;
if(intx>0)
System.out.println("The sign of "+intx+" is + ;");
www.eeworm.com/read/272996/10932209
java signfunction.java
public class SignFunction{
public static void main(String args[]) {
int intx;
intx=0;
if(intx>0)
System.out.println("The sign of "+intx+" is + ;");
www.eeworm.com/read/272181/10967454
c d8_35pf.c
/**********************************************************************
Each of the companies; Lucent, Motorola, Nokia, and Qualcomm (hereinafter
referred to individually as "Source" or collectivel
www.eeworm.com/read/271760/10982080
m satur_non.m
function y=satur_non(x)
if abs(x)>=3, y=2*sign(x); else, y=2/3*x; end
www.eeworm.com/read/469371/6974028
cc 3269704_tle.cc
#include
using namespace std;
typedef struct
{
int value;
int maxvalue;
int sign;
}node;
node mg[200000];
int main()
{
int i,j,t,n,m;
scanf("%d",&t);
www.eeworm.com/read/469371/6974029
cc 3269695_re.cc
#include
using namespace std;
typedef struct
{
int value;
int maxvalue;
int sign;
}node;
node mg[100000];
int main()
{
int i,j,t,n,m;
scanf("%d",&t);
www.eeworm.com/read/469371/6974030
cc 3269698_tle.cc
#include
using namespace std;
typedef struct
{
int value;
int maxvalue;
int sign;
}node;
node mg[200000];
int main()
{
int i,j,t,n,m;
scanf("%d",&t);
www.eeworm.com/read/469371/6974032
cc 3269701_tle.cc
#include
using namespace std;
typedef struct
{
int value;
int maxvalue;
int sign;
}node;
node mg[200000];
int main()
{
int i,j,t,n,m;
scanf("%d",&t);
www.eeworm.com/read/469371/6974070
cc 2908731_wa.cc
#include
using namespace std;
int t,n,num[13];//input
int result[50];
void find(int k,int value,int sign[100],int len)
{
int i;
if(value==0)
{
int ok=0;