代码搜索结果

#include using namespace std; int main() { int i=10,j=20; const int* pi=&i; //指向常量的指针 //*pi=20; //错误1：不能通过pi改变所指向变量的值 cout

#include #define FIRNUMBER 25 #define SIGNAL1F 1000 #define SIGNAL2F 4500 #define SAMPLEF 10000 #define PI 3.1415926 float InputWave(); float FIR(); float fHn[FIRNUMBER]={ 0.0,0

#include"math.h" #define FIRNUMBER 25 #define SIGNAL1F 1000 #define SIGNAL2F 4500 #define SAMPLEF 10000 #define PI 3.1415926 float InputWave(); float FIR(); float fHn[FIRNUMBER]={ 0.0,0

#include"math.h" #define IIRNUMBER 2 #define SIGNAL1F 1000 #define SIGNAL2F 4500 #define SAMPLEF 10000 #define PI 3.1415926 float InputWave(); float IIR(); float fBn[IIRNUMBER]={ 0.0,

%Samp7_6 wp=[0.35 0.65];N=48; %通带边界频率（归一化频率）和滤波器阶数 Fs=50; b=fir1(N,wp); %设计FIR带通滤波器 figure(1) [H,f]=freqz(b,1,512,Fs); %以50Hz为采样频率求出滤波器频率响应 subplot(2,1,1),plot(f,20*log10(abs

%Samp7_5 wp=0.5*pi;ws=0.66*pi; %滤波器的边界频率 wdelta=ws-wp; %过渡带宽度 N=ceil(8* pi/wdelta);%求解滤波器的最小阶数，根据Hanning 窗主瓣宽 Wn=(0.5+0.66)*pi/2;%截止频率取通带和阻带边界频率的中点 b=fir1(N,Wn/pi,hanning(N+1));%

function shili05 h0=figure('toolbar','none',... 'position',[200 150 450 250],... 'name','实例05'); t=0:pi/10:2*pi; [x,y]=meshgrid(t); subplot(2,2,1) plot(sin(t),cos(t)) axis equal sub

function shili06 h0=figure('toolbar','none',... 'position',[200 150 450 400],... 'name','实例06'); t=0:pi/10:2*pi; h=plot(t,sin(t)); xlabel('t=0到2\pi','fontsize',16); ylabel('sin(t)','fon

/*案例代码文件名：AL8_1.C*/ #define PI 3.1415926 /*PI是宏名，3.1415926用来替换宏名的常数*/ main() {float radius,length,area,volume; printf("Input a radius: "); scanf("%f",&radius); length=2*PI*radius;

clear L=100; xmin=-L; xmax=L; n=90; m=6; ne=2*(n-2-1)*(m-1)+2*(m-1); a=zeros(m*(n-2)+2); b=zeros(m*(n-2)+2); xy=zeros(m*(n-2)+2,2); x=zeros(1,m*(n-2)+2); y=zeros(1,m*(n-2)+2); x(1)=xmin;