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Raspberry Pi 的代码
exa100800_corrcoef.m
%------------------------------------------------------------------------
% exa100800_corrcoef.m,
% to test corrcoef.m ;
%------------------------------------------------------------------------
mdefir1.c
#include
#include
#include
#include "msp.h"
void mdefir1(int l,int iband,float fl,float fh,float fs,int iwindow,
float b[],float w[],int *ierror)
{
/*-------------
mvdrb.m
clc;
clear all;
N=48; %% N
k=1000; %% sample number
thetas=10;%信号入射角度
thetai=[-30 30];%干扰入射角度
n=[0:N-1]';%n
sita=45*[-1:0.001:1]; %% s
futex.c
/*
* Fast Userspace Mutexes (which I call "Futexes!").
* (C) Rusty Russell, IBM 2002
*
* Generalized futexes, futex requeueing, misc fixes by Ingo Molnar
* (C) Copyright 2003 Red Hat Inc, All
c5_4_1.m
clear all;
clf;
N=1224;
f1=200;
f2=700;
f3=1100;
dt=1/1024;
sample=1/dt;
randn('state',sum(100*clock));
dis=2*rand(1,
show_tan.c
#include
#include
void main(void)
{
double pi = 3.14159265;
printf("Tangent of pi is %f\n", tan(pi));
printf("Tangent of pi/4 is %f\n", tan(pi / 4.0));
}
main.c
#include
#include
#include
#include
#include
#include
#include
typedef struct tagInterval INTERVAL;
typedef INTERV
chafen1.m
clc;
clear all;
PI=3.14159;
Fs=1;
w=randn(1,256);
a=1;
b=[1,-0.1,0.09,0.648];
x=filter(b,a,w);
t=1:1:256;%256个时间点
figure(5),
plot(t,x);
x1=2*sin(2*PI*0.1*t);
x2=8*sin(2*PI*0.25*t);
x3=8*sin(2*PI*0.
practica2_10a.cpp
/*PRACTICA 2 EJERCICIO 10a
El n鷐ero Pi se puede aproximar por medio de la siguiente serie:
Pi/4 = 2 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11 + 1/13 - 1/15 + ...
a) Escribir un programa que le pregunte al us
show_tan.c
#include
#include
void main(void)
{
double pi = 3.14159265;
printf("Tangent of pi is %f\n", tan(pi));
printf("Tangent of pi/4 is %f\n", tan(pi / 4.0));
}