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Raspberry Pi 的代码
exp2_5_.m
%图形文字标示命令的使用
clear
close all
clc
t=[0:pi/20:5*pi];
plot(t,sin(t),'r:*')
axis([0 5*pi -1.5 1.5 ])
%给x轴和y轴命名
xlabel('t(deg)')
ylabel('magnitude')
%给图形加标题
title('sine wave from zero to 5\pi')
exp2_3.m
%plot绘图命令的使用
clc %清屏命令
clear %清除工作空间中所有变量
%定义时间范围
t=[0:pi/20:9*pi];
y1=sin(t);
y2=cos(t);
plot(t,y1,t,y2)
e_141_02.f90
real*8 a, pai, pi_
a=1.d-307; print *, a, 1./a; print *, tiny(a), huge(a)
b=1.e-39 ; print *, b, 1./b; print *, tiny(b), huge(b)
pi =3.14159265358979_8 ; print *, pi ! pi 无双精度定义,仍为单精度。
a =3.
e_121_02.f90
! ------求圆錐体积和表面积------
PROGRAM Example_1_2
REAL :: pi, r, h, v, s
pi = 3.141593
PRINT *,'Input radius r and height h ?'
READ *, r, h
v = pi*h*r**2/3.0
s = pi*r*(r + sqrt(r**2 + h**2))
fzz.m
function [A0,A,B]=FZZ(func,T, n)
syms t;
func = subs(sym(func), findsym(sym(func)),sym('t'));
A0=int(sym(func),t,-T/2,T/2)/T;
for(k=1:n)
A(k)=int(func*cos(2*pi*k*t/T), t,-T/2,T/2)*2/T;
A
3-4.m
%例程3-4 产生锯齿波形
Fs=1000;
t=0:1/Fs:3;
x=sawtooth(2*pi*t);
y=sawtooth(2*pi*t,0.5);
z=sawtooth(2*pi*t,1);
subplot(3,1,1);
plot(t,x);
subplot(3,1,2);
plot(t,y);
subplot(3,1,3);
plo
3-12.m
%例程3-12 求解单位冲击响应的幅频
N=20;
a=[0.4 0.3 -1];
b=[1 -0.2 0.6 0.3];
x=[1 zeros(1,N-1)];
k=0:N-1;
y=filter(a,b,x);
Fs=1000;
w=0:pi/Fs:pi;
h=freqz(a,b,w);
subplot(2,1,1);
stem(k,y);
3-1.m
%例程3-1 计算序列抽样和与序列能量
t=(0:0.1:10)';
x=sin(2*pi*t)+2*cos(pi*t);
y=x+randn(size(t));
s=sum(x(1:100));
E=sum(abs(y).^2);
subplot(2,2,1);
plot(t,x);
title('X');
subplot(2,2,2);
plot(t,y);
ti
4-25.m
%例程4-25 基于频率抽样方法2实现Ⅲ型FIR数字带通滤波器
clear all;
N=41;
T1=0.1095;
alpha= (N-1)/2;
l=0:N-1;
wl= (2*pi/N)*l;
Hrs=[zeros(1,6),T1,ones(1,7),T1,zeros(1,11),T1,ones(1,7),T1,zeros(1,6)];
4-24.m
%例程4-24 基于频率抽样方法1实现Ⅰ型FIR数字高通滤波器
clear all;
N=61;
T1=0.1095;
T2=0.598;
alpha= (N-1)/2;
l=0:N-1;
wl= (2*pi/N)*l;
Hrs=[zeros(1,22),T1,T2,ones(1,14),T2,T1,zeros(1,21)]; %理想振幅采样响应
Hdr