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找到约 10,000 项符合 Raspberry Pi 的代码

gngauss.m

function grsv=gngauss(m,sgma) if(nargin==0), m=0; sgma=1; elseif nargin==1 sgma=m; m=0; end; u=rand; z=sgma*(sqrt(2*log(1/(1-u)))); u=rand; grsv(1)=m+z*cos(2*pi*u); grsv

4-7.txt

/* 范例:4-7 */ #include #include void main() { char name[20]; char sex; int age; float pi; printf("请输入您的姓名:"); scanf("%s",name); /* #1 */ printf("请输入您的性别(

fft1234.m

f1=1;%f1=8;坐标调整在横轴0-32,每隔4个点去一个,效果最好 f2=12.375; ts=1; fs=1000; t=0:1/fs:0.2;%t=0:1/fs:0.15;%不在一个完整周期内的采样,共取了150个点 %均值为0,方差为1的白色噪声 ww1=normrnd(0,1,1,size(t));%调节SNR数值的时候只需调方差即可 %带通滤波器,使白噪声通过后变成有

fm.m

function y = FM(x,beta) [r, c] = size(x); if r*c == 0 y = []; return; end; if (r == 1) x = x(:); len = c; else len = r; end; Df = 2*pi*beta*100; x = interp(x,20)

hrollfcoef.m

% Program 3-3 % hrollfcoef.m % % Generate coefficients of Nyquist filter % % programmed by H.Harada % function [xh] = hrollfcoef(irfn,ipoint,sr,alfs,ncc) %****************** variables ****

music_1.txt

clear; d=1; M=8; N=2; lma=2; sam=200; q=[20,40];%信源方向 A=exp(-2*pi*j*d*[0:M-1]'*sin(q*pi/180)/lma); n=1:sam; v1=1000000000000; v2=3000000000005; SNR=10; Am=10^(SNR/20); signal=Am*[cos(v1*n

sample.c

/* * Example program * * Copyright (c) 1988-1997 Shamus Software Ltd. */ #include #include "miracl.h" int main() { /* Brents example program */ flash x,pi; mira

project_1.m

%项目一 用MATLAB验证时域抽样定理 TN=0.05;TNN=0.005; %前者为抽样间隔 后者是对原始信号采样画图 Ts1=0.02;Ts2=0.08; %两种抽样时间 分别>

例3.12.txt

例3.12 用下面公式求π的近似值。π/4≈1-1/3+1/5-1/7+…直到最后一项的绝对值小于10的-7次方为止。 根据给定的算法很容易编写程序如下: #include #include #include using namespace std; int main( ) {int s=1; double n=1

iir.m

wp=0.2*pi;Rp=1;ws=0.3*pi;As=15; [n,wn]=buttord(wp,ws,Rp,As,'s') [z,p,k]=buttap(n); [bap,aap]=zp2tf(z,p,k) [b,a]=lp2lp(bap,aap,wn); [db,mag,pha,w]=freqs_m(b,a,0.5*pi); [ha,x,t]=impulse(b,a); fig