代码搜索结果
找到约 10,000 项符合
Raspberry Pi 的代码
例3.12.txt
例3.12 用下面公式求π的近似值。π/4≈1-1/3+1/5-1/7+…直到最后一项的绝对值小于10的-7次方为止。
根据给定的算法很容易编写程序如下：
#include
#include
#include
using namespace std;
int main( )
{int s=1;
double n=1
circle.java
class Circle
{
public int Radius;
public float Length;
public float Area;
final double PI=3.14159;
public void Calculate( Graphics g,int x)
{
Length = 2 * PI * Radius;
Area = PI
xt3-2.cpp
#include
#include
using namespace std;
int main ( )
{float h,r,l,s,sq,vq,vz;
const float pi=3.1415926;
coutr>>h;
l=2*pi*r;
s=r*r*pi;
sq
c13-2.cpp
#include
#include
using namespace std;
int main()
{int a;
couta;
cout
c13-3.cpp
#include
using namespace std;
int main()
{int a=21;
cout.setf(ios::showbase);
cout
c3-12.cpp
#include
#include
#include
using namespace std;
int main()
{int s=1;
double n=1,t=1,pi=0;
while((fabs(t)) > 1e-7)
{pi=pi+t;
n=n+2;
s=-s;
t=s/n;
program2_09.c
/* Program 2.9 More round tables */
#include
#define PI 3.14159f /* Definition of the symbol PI */
int main(void)
{
float radius = 0.0f;
float diameter = 0.0f;
2408934_wa.c
#include
#include
#define zero 1e-1
#define PI 3.141592653
int main()
{
double l1, l2, l3;
double a1, a2, a3;
double x1, x2, x3, y1, y2, y3;
while(scanf("%lf%lf%lf%lf
2409002_wa.c
#include
#include
#define zero 1e-1
#define PI 3.141592653
int main()
{
double l1, l2, l3;
double a1, a2, a3;
double x1, x2, x3, y1, y2, y3;
while(scanf("%lf%lf%lf%lf
2408927_wa.c
#include
#include
#define zero 1e-2
#define PI 3.141592653
int main()
{
double l1, l2, l3;
double a1, a2, a3;
double x1, x2, x3, y1, y2, y3;
while(scanf("%lf%lf%lf%lf