代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/278599/10526683
m ex5_13.m
x=0:pi/10:2*pi;
y=2*sin(x);
subplot(2,2,1);bar(x,y,'g');
title('bar(x,y,''g'')');axis([0,7,-2,2]);
subplot(2,2,2);stairs(x,y,'b');
title('stairs(x,y,''b'')');axis([0,7,-2,2]);
subplot(2,2,3);ste
www.eeworm.com/read/278599/10526727
m ex10_2.m
x=0:pi/50:2*pi;
y=sin(x);
z=cos(x);
plot(x,y,'r',x,z,'g'); %绘制两根不同曲线
Hl=get(gca,'Children'); %获取两曲线句柄向量Hl
for k=1:size(Hl)
if get(Hl(k),'Color')==[0 1 0] %[0 1 0]代表
www.eeworm.com/read/278599/10526732
m ex5_5.m
x=0:pi/100:2*pi;
y1=0.2*exp(-0.5*x).*cos(4*pi*x);
plot(x,y1)
hold on
y2=2*exp(-0.5*x).*cos(pi*x);
plot(x,y2);
hold off
www.eeworm.com/read/423914/10526818
m ex082900.m
% Chapter 8: Example 8.29
% Elliptic Bandpass Filter Design:
% Use of the ELLIP function
%
% 第八章: 例 8.29
% 椭圆带通滤波器设计
% ELLIP函数的应用
%
% 数字低
www.eeworm.com/read/423914/10526855
m ex082800.m
% 第八章: 例 8.28
% 切比雪夫-1高通滤波器设计
% CHEBY1函数的应用
%
% 数字低通滤波器指标: % 切比雪夫-1型高通:
ws = 0.4586*pi; % 数字阻带边缘频率
wp = 0.6*pi;
www.eeworm.com/read/423914/10526876
m ex083000.m
% 第八章: 例 8.30
% 切比雪夫-2带阻滤波器设计
% CHEBY2函数的应用
%
% 数字低通滤波器指标: % 切比雪夫-2型带阻:
ws = [0.4*pi 0.7*pi]; % 数字阻带边缘频率
wp = [0.25*pi 0.8*pi];
www.eeworm.com/read/423913/10526908
m ex072200.m
% 第七章: 例 7.22
% 误差函数图和极值的数目
figure(1);subplot(1,1,1)
h = [1,2,3,4,3,2,1]/15;
M = length(h); n = 0:M-1;
[Hr,w,a,L] = Hr_Type1(h);
subplot(1,2,1);plot(w/pi,Hr);axis([0,1,-0.05,1.1])
xlabel('频率（单位
www.eeworm.com/read/423913/10526919
m ex071600.m
% 第七章: 例 7.16
% 频率采样技术: 低通, 最优法T1 & T2
% wp = 0.2pi, ws=0.3pi, Rp=0.25dB, As=50dB
% T1 = 0.5925, T2=0.1099
M = 60; alpha = (M-1)/2; l = 0:M-1; wl = (2*pi/M)*l;
Hrs = [ones(1
www.eeworm.com/read/160490/10526944
m cp0702_analytical_waveforms.m
%
% FUNCTION 7.3 : "cp0702_analytical_waveforms"
%
% Definition of the analytical expression for the first 15
% derivatives of the Gaussian pulse
%
% The function receives in input:
% 1) the ti
www.eeworm.com/read/423913/10526955
m ex072500.m
% 第七章 例 7.25
% 用PM算法进行的高通滤波器设计
%
ws = 0.6*pi; wp = 0.75*pi; Rp = 0.5; As = 50;
delta1 = (10^(Rp/20)-1)/(10^(Rp/20)+1);
delta2 = (1+delta1)*(10^(-As/20));
deltaH = max(delta1,delta2); deltaL = m