代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/353872/10411127
m gamicheval.m
function [sol,val] = gaMichEval(sol,options)
val = 21.5 + sol(1) * sin(4*pi*sol(1)) + sol(2)*sin(20*pi*sol(2));
%G=zeros(0);
%val = sqrt(sol(1)) * sin(2*sol(1)) + sqrt(sol(1))*cos(5*sol(1))+5;
www.eeworm.com/read/279576/10413042
m untitled.m
%sjbh.m
function sjbh1(m)
x=-1:0.01:10;
y1=sin(x);
plot(x,y1)
axis([-1 10 -2 2])
grid
legend('sin(x)')
pause(2)
legend off
legend('将y=sin(x)的横坐标收缩至原来的1/2')
%hold on
%theax=axis;
pause
%y
www.eeworm.com/read/279576/10413048
m sjbh.m
%sjbh.m
%function sjbh1(m)
x=-1:0.01:10;
y1=sin(x);
plot(x,y1)
axis([-1 10 -2 2])
grid
legend('sin(x)')
pause(2)
legend off
legend('将y=sin(x)的横坐标收缩至原来的1/2')
%hold on
%theax=axis;
pause
%
www.eeworm.com/read/279576/10413051
m sjbh1.m
%sjbh.m
function sjbh1(m)
x=-1:0.01:10;
y1=sin(x);
plot(x,y1)
axis([-1 10 -2 2])
grid
legend('sin(x)')
pause(2)
legend off
legend('将y=sin(x)的横坐标收缩至原来的1/2')
%hold on
%theax=axis;
pause
%y
www.eeworm.com/read/424747/10418304
m gamicheval.m
function [sol,val] = gaMichEval(sol,options)
val = 21.5 + sol(1) * sin(4*pi*sol(1)) + sol(2)*sin(20*pi*sol(2));
%G=zeros(0);
%val = sqrt(sol(1)) * sin(2*sol(1)) + sqrt(sol(1))*cos(5*sol(1))+5;
www.eeworm.com/read/353665/10432428
m doaestimate3.m
%music.m
clear
clear all
%构造信号源
n=-pi:2.0/2000*pi:pi; %范围
fs=2000;
f1=0.015;
f2=0.05;
f3=0.02;
f4=0.035;
%s1=100*randn(1)*cos(100*randn(1)*sqrt(2.0)*pi*n+pi*randn(1)); %构造四个余弦信号
%s2=1
www.eeworm.com/read/353665/10432441
m doaestimate2.m
%music.m
clear
clear all
%构造信号源
n=-pi:2.0/2000*pi:pi; %范围
fs=2000;
f1=0.015;
f2=0.05;
f3=0.02;
f4=0.035;
%s1=100*randn(1)*cos(100*randn(1)*sqrt(2.0)*pi*n+pi*randn(1)); %构造四个余弦信号
%s2=1
www.eeworm.com/read/161189/10440056
m examp.m
%
% Reinitialize everything.
%
clear
rand('seed',0);
randn('seed',0);
%
% Get the problem.
%
load shawexamp.mat
%
% Set the data covariance matrix.
%
CD=1.0e-12*eye(20);
%
% Setup the prior.
%
mprior=
www.eeworm.com/read/353524/10441489
m ex040400.m
% 第四章: 例 4.4:
% 用 ztrans 求 X(z)
% x(n) = (n-2)(0.5)^(n-2)cos[pi*(n-2)/3]u(n-2)
x = 'n*((0.5)^n)*cos(pi*n/3)';
X = ztrans(x);
[nX,dX] = numden(X);
nX=expand(nX)
dX = symmul(dX,'z^2'); dX=exp
www.eeworm.com/read/353524/10441512
m ex041100.m
% 第四章: 例4.11:
% z-平面函数:
% a)
b = [1,0]; a = [1, -0.9];
pzplotz(b,a); title('极点-零点图');
text(0.85,-0.1,'0.9');text(0.01,-0.1,'0');pause,
print -deps fg0407.eps
% b)
[H,w]=freqz(b,a,100);
magH