代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/162323/10314316
m exp2_5_.m
%图形文字标示命令的使用
clear
close all
clc
t=[0:pi/20:5*pi];
plot(t,sin(t),'r:*')
axis([0 5*pi -1.5 1.5 ])
%给x轴和y轴命名
xlabel('t(deg)')
ylabel('magnitude')
%给图形加标题
title('sine wave from zero to 5\pi')
www.eeworm.com/read/162323/10314323
m exp2_3.m
%plot绘图命令的使用
clc %清屏命令
clear %清除工作空间中所有变量
%定义时间范围
t=[0:pi/20:9*pi];
y1=sin(t);
y2=cos(t);
plot(t,y1,t,y2)
www.eeworm.com/read/354915/10314554
m exa060603.m
%----------------------------------------------------------------------------
% exa060603.m, for example 6.6.3;
% To design IIR Butteworth bandstop DF by analog-lowpass,
% -------------------------
www.eeworm.com/read/354915/10314625
m exa011004_sinc.m
%-----------------------------------------------------------------
% exa011004_sinc.m, for example 1.10.4
% to generate the sinc function.
% 产生一 sinc 函数；
%-----------------------
www.eeworm.com/read/354915/10314655
m exa050501.m
%------------------------------------------------------------------------
% exa050501.m, for example 5.5.1 and fig5.5.1
% to explain the spectra factorization
%------------------------------------
www.eeworm.com/read/354915/10314742
m exa060701_3.m
%-----------------------------------------------------------------------------
% exa060701_3.m , for example 6.7.1 and 6.5.1
% to test butter.m
%---------------------------------------------------
www.eeworm.com/read/354915/10314752
m exa060701_2.m
%-----------------------------------------------------------------------------
% exa060701_2.m , for example 6.7.1 and 6.5.1
% to test buttord,lp2lp,bilinear ;
% to design Low-pass DF with s=2/Ts[(
www.eeworm.com/read/354915/10314789
m exa100800_corrcoef.m
%------------------------------------------------------------------------
% exa100800_corrcoef.m,
% to test corrcoef.m ;
%------------------------------------------------------------------------
www.eeworm.com/read/354899/10316896
m feedb.m
% feedbl.m
% 反馈线性化
% 初始化
clear
X1 = [rand(1,300)*pi, rand(1,100)*pi];
X2 = [rands(1,300)*pi, zeros(1,100) ];
P = [X1; X2];
dt = 0.05;
T= X2 + dt*(10*sin(X1)-2*(X2));
[R,Q] = size(P);
S1
www.eeworm.com/read/162242/10323375
m langrange.m
%Langrange插值法
function y=Langrange(x1,y1,x);
m=length(x);
n=length(x1);
for i=1:m
y(i)=0;
for j=1:n
l=1;
for k=1:n
if (k~=j)
l=(x(i)-x1(k)