代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/163503/10156719
cpp main.cpp
#include
#include
using namespace std;
int main(int argc, char *argv[])
{
//3.19
/* int ival=1;
//int &rval1=1.01;这样的赋值不正确
int &rval1=ival;
cout
www.eeworm.com/read/359245/10159365
m exa5_16.m
%-----------------------------------------------------------------------------
% exa060402_fresam2.m , for example 6.4.2
% use frequency sampling method 2 to design bandpass digital filter
%-------
www.eeworm.com/read/359245/10159374
m exa5_26.m
%--------------------------------------------------------------------------
% exa060609_cremez.m, for example 6.6.9;
% to test cremez and to design allpass FIR filter;
%--------------------------
www.eeworm.com/read/359245/10159392
m exa5_15.m
%-----------------------------------------------------------------------------
% exa060401_fresam1.m , for example 6.4.1
% use frequency sampling method 1 to design highpass digital filter
%-------
www.eeworm.com/read/359245/10159441
m exa6_23.m
%exa060402_peig.m, for example 6.4.2
%to test peig.m;
clear all;
%信号序列产生；
randn('state',1);
N=1000; %采样点数
n=0:N-1;
en=randn(1,N);
xn=exp(j*pi/2*n)+2*exp(j*pi/4*n)+exp(j*pi/3*n)+en;
%
www.eeworm.com/read/359245/10159454
m exa6_5.m
% exa060201_corrcoef.m,
% to test corrcoef.m ;
clear all;
N=256;
f=.1;a1=5;a2=3;
x=a1*sin(2*pi*f*(0:N-1))+2*randn(1,N);
y=a2*sin(2*pi*f*(0:N-1))+randn(1,N);
% 求数据向量 x 和 y 的相关系数矩阵
www.eeworm.com/read/359245/10159463
m exa6_22.m
%exa060401_MUSIC.m, for example 6.4.1
%to test MUSIC.m;
clear all;
%信号序列产生；
randn('state',1);
N=1000; %采样点数
n=0:N-1;
en=randn(1,N);
xn=exp(j*pi/2*n)+2*exp(j*pi/4*n)+exp(j*pi/3*n)+en;
www.eeworm.com/read/359245/10159544
m exa1_34.m
% exa1-34_rectpuls.m for example 1-34
% rectpuls function
clear all;
fs=100; %sample frequency
x=0:1/fs:pi;
w=3;
y=rectpuls(x,w);
plot(x,y)
axis([0 pi 0 1.1])
www.eeworm.com/read/359245/10159593
m exa4_12.m
% exa4-12_butterstopDF.m , for example 4-12
% using butterworth to design bandstop DF
clear all;
Wp=[0.4*pi,0.7*pi];
Ws=[0.2*pi,0.8*pi];
Ap=1;
As=30;
[N,wn]=buttord(Wp/pi,Ws/pi,Ap,As); %计算巴特沃
www.eeworm.com/read/359245/10159596
m exa4_8.m
% exa4-8_pulseDF for example4-8
% using Butterworth analog lowpass filter to design digital lowpass filter
%利用模拟Butterworth滤波器设计数字低通滤波器
%脉冲响应不变法
wp=0.2*pi;
ws=0.3*pi;
Rp=1;
As=15;
T=1;
%性能