代码搜索:Raspberry Pi

找到约 10,000 项符合「Raspberry Pi」的源代码

代码结果 10,000
www.eeworm.com/read/379493/9194851

c fir.c

///////////////////////////////////////////////// // Example For ICETEK-VC5416-EDU // // CTR Version : V4 // // Filename: Fir.c
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cpp p1-98.cpp

#include //以下是几个简单宏替换预处理指令 #define YES 1 #define PI 3.1415926 #define RAD PI/180 #define MESG "This is a string." //以下是主程序 main() { //以下各语句使
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cpp p1-12.cpp

#include const double PI=3.1416; //声明常量(const变量)PI为3.1416 main() { //声明3个变量 double r,l,s; //输入圆的半径 coutr; //计算圆的周长
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cpp p1-100.cpp

#include #define PI 3.1416 main() { int i=100; #if 1 cout
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m hrollfcoef.m

% Program 3-3 % hrollfcoef.m % % Generate coefficients of Nyquist filter % % programmed by H.Harada % function [xh] = hrollfcoef(irfn,ipoint,sr,alfs,ncc) %****************** variables ****
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m hrollfcoef.m

% Program 3-3 % hrollfcoef.m % % Generate coefficients of Nyquist filter % % programmed by H.Harada % function [xh] = hrollfcoef(irfn,ipoint,sr,alfs,ncc) %****************** variables ****
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m toeplitz_page110.m

%%%%%%可能是程序写的不好,算法的仿真结果不行,分辨力较差@@@@@@@@@ clc; clear ; close all; tic M=20;%阵元数目 N=3;%信源数目 b=5;%形成的波束个数 snap=1000;%快拍数目 C=3e8; f0=10e6; lamda=C/f0; d=0.5*lamda; % k=d/lamda; theta0=50; t
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cpp 2.1.cpp

#include const double pi=3.14159265; void main() { double a,r; r=1.5; a=pi*r*r; cout
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cpp 5.5.cpp

#include void main() { int i,*pi1=&i,*pi2; double d,*pd1=&d,*pd2; pi2=pi1+1; pd2=pd1+1; cout
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c gaussian.c

#include #define pi 3.1415 double gaussian(double x) { double resu; resu=-0.5*x*x; resu=exp(resu); resu=resu/sq